In a three-phase system, power is measured by two wattmeter method. If the reading of the wattmeters are +1000 W and -1000 W, then which of the following is correct?

This question was previously asked in
MPPKVVCL Line Attendant 26 Aug 2017 Official Paper
View all MPPGCL Line Attendant Papers >
  1. Power factor of load is zero and total power is zero
  2. Power factor of load is one and total power is zero
  3. Power factor of load is zero and total power is 2000
  4. Power factor of load is one and total power is 2000

Answer (Detailed Solution Below)

Option 1 : Power factor of load is zero and total power is zero
Free
MPPKVVCL Line Attendant Electrical Machine Mock Test
1.8 K Users
20 Questions 20 Marks 24 Mins

Detailed Solution

Download Solution PDF

Explanation:

Two Wattmeter Method in a Three-Phase System

Definition: The two wattmeter method is a technique used to measure power in a three-phase system. It involves connecting two wattmeters to the system in such a way that they measure the power consumed in the three-phase load. This method is particularly useful for both balanced and unbalanced loads.

Working Principle: In the two wattmeter method, the wattmeters are connected in such a way that each wattmeter measures the power in one phase of the three-phase system. The total power consumed by the load is the algebraic sum of the readings of the two wattmeters. The readings of the wattmeters depend on the power factor of the load and the phase angle between the line voltages and the currents.

Measurement and Analysis:

  • Power Measured by Wattmeters: Let the readings of the two wattmeters be W1 and W2.
  • In a balanced three-phase system, the total power (P) consumed by the load is given by:
    P = W1 + W2
  • The power factor (pf) of the load can be determined using the readings of the two wattmeters:
    pf = cos(θ) = (W1 - W2) / (W1 + W2)
  • Given: The readings of the wattmeters are +1000 W and -1000 W.

Calculations:

  • Total Power:
    P = W1 + W2 = 1000 W + (-1000 W) = 0 W
  • Power Factor:
    pf = cos(θ) = (W1 - W2) / (W1 + W2) = (1000 W - (-1000 W)) / (1000 W + (-1000 W)) = 2000 W / 0 W
    Since the denominator is zero, the power factor is undefined in a real-world sense, but it indicates that the phase angle is 90 degrees, leading to a power factor of zero.

Conclusion:

Option 1: Power factor of load is zero and total power is zero.

This option is correct because the total power calculated is zero, and the power factor is zero, which corresponds to a purely reactive load where the voltage and current are 90 degrees out of phase.

Additional Information

To further understand the analysis, let’s evaluate the other options:

Option 2: Power factor of load is one and total power is zero.

This is incorrect because a power factor of one (unity) implies that the load is purely resistive, and in such a case, the wattmeter readings would not be equal and opposite. Instead, both wattmeters would show positive readings, and their sum would not be zero.

Option 3: Power factor of load is zero and total power is 2000.

This is incorrect because while the power factor is indeed zero, the total power calculated from the given wattmeter readings is zero, not 2000 W.

Option 4: Power factor of load is one and total power is 2000.

This is incorrect because a power factor of one implies a purely resistive load, which would result in both wattmeters showing positive readings. Additionally, the total power calculated from the given readings is zero, not 2000 W.

Conclusion:

The two wattmeter method provides valuable insights into the power consumption and power factor of a three-phase system. By analyzing the readings of the wattmeters, one can determine the total power and the nature of the load. In this case, the readings indicate a purely reactive load with a power factor of zero and a total power of zero, making option 1 the correct choice.

Latest MPPGCL Line Attendant Updates

Last updated on May 29, 2025

-> MPPGCL Line Attendant result 2024 has been released at the official website.

-> M.P. Power Generating Company Limited has released the exam date for Line Attendants.

-> A total of 1196 vacancies have been released.

-> Candidates had submitted their online applications from 24th December 2024 to 23rd January 2025.

-> Candidates must have an upper age limit of 40 years for males and 45 years for females.

-> The responsibilities of an MPPGCL Line Attendant include maintaining and repairing electrical power lines, ensuring a steady power supply, conducting inspections, resolving faults, and adhering to safety standards in power line operations.

More Measurement of Power Questions

Get Free Access Now
Hot Links: teen patti master list teen patti 51 bonus teen patti master official teen patti earning app