In a circuit shown below, the collector current at Q-point is:

F1 Madhuri Engineering 19.12.2022 D28

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  1. \(\rm \frac{V_{CC}-V_{BE}}{R_B}\)
  2. \(\rm \beta. \frac{V_{CC}-V_{BE}}{R_C}\)
  3. \(\rm \beta. \frac{V_{CC}-V_{BE}}{R_B}\)
  4. \(\rm \beta. \frac{V_{CC}-V_{BE}}{R_B+R_C}\)

Answer (Detailed Solution Below)

Option 3 : \(\rm \beta. \frac{V_{CC}-V_{BE}}{R_B}\)
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Detailed Solution

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Concept:

Q-point is an abbreviation of quiescent point, it’s the point where the transistor is currently operating at. i.e the current values of Vce and Ic on the I-V characteristics graph of BJT.(also applies for MOSFETs).

Q-point is controlled by a load line on the I-V graph, Load line is a line that connects the maximum Ic and Vce the transistor can handle for a certain circuit. (On the same graph), Q-point must be anywhere on that line.

F1 Madhuri Engineering 19.12.2022 D29

Analysis:

F1 Madhuri Engineering 19.12.2022 D28

For DC analysis open circuit of the capacitors.

F1 Madhuri Engineering 19.12.2022 D31

Then;

Base current:

\(I_{B} = \frac{V_{CC}-V_{BE}}{R_{B}}\)

Collector current:

\(I_{C}=\beta I_{B} = \beta.\frac{V_{CC}-V_{BE}}{R_{B}}\)

 

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