Question
Download Solution PDFIf \(\rm z=\frac{1}{3}\begin{vmatrix}i&2i&1\\\ 2i&3i&2\\\ 3&1&3\end{vmatrix}=x+iy;i=\sqrt{-1}\) then what is modulus of Z equal to?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Given
\(\rm z=\frac{1}{3}\begin{vmatrix}i&2i&1\\\ 2i&3i&2\\\ 3&1&3\end{vmatrix}\)
\(Z = \frac{1}{3}[[ (i9 – 2) – 2i (6i – 6) 1(2i – 9i)]\)
\(Z = \frac{1}{3}[3+3i] =1 + i \)
|Z| = \(√{1^2+1^2} =\) √2
∴ Option (b) is correct.
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