Question
Download Solution PDFIf A, B are square matrices of the same order and B is a skew-symmetric matrix, then A′BA is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Transpose of a Matrix:
The new matrix obtained by interchanging the rows and columns of the original matrix is called as the transpose of the matrix.
For example: \(\rm A=\begin{bmatrix} \rm a & \rm b \\ \rm x & \rm y \end{bmatrix}\Rightarrow A'=\begin{bmatrix} \rm a & \rm x \\ \rm b & \rm y \\ \end{bmatrix}\).
It is denoted by A' or AT.
Properties of Transpose of a Matrix:
- The transpose of the product of two matrices is equivalent to the product of their transposes in reversed order:
(AB)' = B'A'
-
(ABC)' = C'B'A'
-
(A')' = A
Calculation:
It is given that B is a skew-symmetric matrix.
∴ B' = -B
Now, consider the transpose of the product matrix A′BA.
(A′BA)' = A'B'(A')'
= A'(-B)A [∵ B' = -B]
= -(A'BA)
Since the transpose is equal to its negative, A'BA is a Skew-Symmetric matrix.
Last updated on Jun 18, 2025
->UPSC has extended the UPSC NDA 2 Registration Date till 20th June 2025.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.