Answer (Detailed Solution Below)

Option 3 : 13
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Detailed Solution

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Concept:

Permutations and Combinations:

  • nPr = \(\rm \frac{n!}{(n - r)!}\).
  • n! = 1 × 2 × 3 × ... × n.
  • 0! = 1.

 

Calculation:

Expanding the expression on both sides of the equation, we get:

2nP3 = 100 nP2

⇒ \(\rm \frac{2n!}{(2n - 3)!}=100\frac{n!}{(n - 2)!}\)

⇒ \(\frac{2n (2n - 1) (2n - 2)(2n - 3)!}{(2n - 3)!}=100\times \frac{n(n-1)(n-2)!}{(n-2)!}\)

(2n)(2n - 1)(2n - 2) = 100(n)(n - 1)

⇒ 2n - 1 = 25, n ≠ 1.

⇒ n = 13.

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