Question
Download Solution PDF7x2 - 9y2 = 63 की उत्केंद्रता क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
अतिपरवलय:
|
समीकरण |
|
|
|
अनुप्रस्थ अक्ष का समीकरण |
y = 0 |
x = 0 |
|
संयुग्म अक्ष का समीकरण |
x = 0 |
y = 0 |
|
अनुप्रस्थ अक्ष की लंबाई |
2a |
2a |
|
संयुग्म अक्ष की लंबाई |
2b |
2b |
|
शीर्ष |
(± a, 0) |
(0, ± a) |
|
फोकस |
(± ae, 0) |
(0, ± ae) |
|
संचालिका |
x = ± a/e |
y = ± a/e |
|
केन्द्र |
(0, 0) |
(0, 0) |
|
उत्केंद्रता |
|
|
|
नाभिलंब की लंबाई |
|
|
|
बिंदु (x, y) की फोकल दूरी |
ex ± a |
ey ± a |
गणना:
दिया गया समीकरण निम्न है,
7x2 - 9y2 = 63, जिसे इसप्रकार लिखा जा सकता है,
इसलिए, यह a2 = 9 और b2 = 7 के साथ एक अतिपरवलय है
उत्केंद्रता होगी,
e2 = 1 +
तो, e2 = 1 +
इसलिए, e2 =
⇒ e =
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