Question
Download Solution PDFएक स्प्रिंग की कठोरता 20 N/cm है। स्प्रिंग को 7 cm तक खींचने के लिए किए गए कार्य की गणना करें।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
स्प्रिंग द्वारा किए गए कार्य की गणना इस प्रकार की जाती है:
\(W=\frac {1}{2} KX^2\)
जहाँ W = जूल में किया गया कार्य
K = कठोरता N/cm में
X = विस्थापन cm में
गणना:
दिया गया:
K = 20 N/cm
X = 7 cm
किया गया कार्य =\(\frac {1}{2} \times 20 \times7^2 = 490\) N cm = 4.9 जूल
अतः किया गया कार्य 4.9 जूल है।
Last updated on May 9, 2025
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