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नीचे दिखाई गई अनुक्रिया की प्रकृति __________ होगी। 

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MPPKVVCL Indore JE Electrical 21 August 2018 Official Paper
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  1. ζ = 0.894 और ωn = 20 rad/s के साथ अति अवमंदित ​
  2. ζ = 1.894 और ωn = 4.472 rad/s के साथ न्यून अवमंदित
  3. ζ = 1.894 और ωn = 20 rad/s के साथ अति अवमंदित ​
  4. ζ = 0.894 और ωn = 4.472 rad/s के साथ न्यून अवमंदित

Answer (Detailed Solution Below)

Option 4 : ζ = 0.894 और ωn = 4.472 rad/s के साथ न्यून अवमंदित
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Detailed Solution

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संकल्पना

द्वितीय कोटि के स्थानांतरण फलन को निम्न के द्वारा प्रदर्शित किया गया है:

जहाँ, ωn = स्वाभाविक आवृत्ति 

ζ = अवमंदन अनुपात 

अवमंदन अनुपात के संबंध में अवमंदन की प्रकृति निम्नानुसार होगी:

अवमंदन अनुपात

अवमंदन

ζ = 0

अनवमंदित 

0 < ζ < 1

न्यून अवमंदित 

ζ = 1

क्रांतिकत अवमंदित 

ζ > 1

अति अवमंदित ​

गणना

दिया गया है, 

ωn =4.472 rad/s

2ζωn = 8

ζ = 0.894

इसलिए, यह प्रणाली न्यून अवमंदित है।​

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