A (2, -3, 3), B (5, -3, -4) और C (2, -3, -2) शीर्षों वाले एक त्रिभुज का केन्द्रक कौन-सा बिन्दु है?

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  1. (-3, 3, -1)
  2. (3, -3, -1)
  3. (3, 1, -3)
  4. (-3, -1, -3)

Answer (Detailed Solution Below)

Option 2 : (3, -3, -1)
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धारणा:

यदि A (x1, y1, z1), B (x2, y2, z2) और C (x3, y3, z3) ΔABC के शीर्ष हैं तो ΔABC का केंद्रक निम्न द्वारा दिया जाता है: \(\left( {\frac{{{x_1} + {x_2} + {x_3}}}{3},\frac{{{y_1} + {y_2} + {y_3}}}{3},\frac{{{z_1} + {z_2} + {z_3}}}{3}} \right)\)

गणना:

दिया हुआ: ΔABC के शीर्ष हैं: A(2, -3, 3), B(5, -3, -4) और C(2, -3, -2)

जैसा कि हम जानते हैं कि, यदि A (x1, y1, z1), B (x2, y2, z2) और C (x3, y3, z3) ΔABC के शीर्ष हैं तो ΔABC का केंद्रक निम्न द्वारा दिया जाता है: \(\left( {\frac{{{x_1} + {x_2} + {x_3}}}{3},\frac{{{y_1} + {y_2} + {y_3}}}{3},\frac{{{z_1} + {z_2} + {z_3}}}{3}} \right)\)

\(\Rightarrow \;\left( {\frac{{2 + 5 + 2}}{3},\frac{{ - \;3 - 3 - 3}}{3},\frac{{3 - 4 - 2}}{3}} \right) = \left( {3,\; - 3,\; - 1} \right)\)
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