Question
Download Solution PDFवक्र y = x - 1 और y2 = 2x + 6 से घिरा क्षेत्रफल का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFव्याख्या:
दिए गए वक्र y = x - 1 और y2 = 2x + 6 हैं।
इन्हे हल करने पर हमें प्राप्त होगा,
y2 = 2(y + 1) + 6
⇒ y2 - 2y - 8 = 0
⇒ (y - 4)(y + 2) = 0
⇒ y = -2, 4
अब, हम निम्न के द्वारा क्षेत्रफल ज्ञात कर सकते हैं
A = \(\int_{-2}^{4}\left [y+1-\left ( \frac{y^{2}}{2}-3 \right ) \right ]dy \)
= \(\int_{-2}^{4}\left (4+y-\frac{y^{2}}{2} \right )dy \)
= \(\left [ 4y+\frac{y^{2}}{2} -\frac{y^{3}}{6}\right ]_{-2}^{4}\)
= \(16+8-\frac{32}{3}-\left ( -8+2+\frac{4}{3} \right )\)
∴ A = 18
Last updated on Jun 19, 2025
-> The AAI ATC Exam 2025 will be conducted on July 14, 2025 for Junior Executive..
-> AAI JE ATC recruitment 2025 application form has been released at the official website. The last date to apply for AAI ATC recruitment 2025 is May 24, 2025.
-> AAI JE ATC 2025 notification is released on April 4, 2025, along with the details of application dates, eligibility, and selection process.
-> A total number of 309 vacancies are announced for the AAI JE ATC 2025 recruitment.
-> This exam is going to be conducted for the post of Junior Executive (Air Traffic Control) in the Airports Authority of India (AAI).
-> The Selection of the candidates is based on the Computer-Based Test, Voice Test and Test for consumption of Psychoactive Substances.
-> The AAI JE ATC Salary 2025 will be in the pay scale of Rs 40,000-3%-1,40,000 (E-1).
-> Candidates can check the AAI JE ATC Previous Year Papers to check the difficulty level of the exam.
-> Applicants can also attend the AAI JE ATC Test Series which helps in the preparation.