δ(ω - ω0) का व्युत्क्रम फॉरियर रूपांतरण__________है। 

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  1. \(\frac{2π}{e^{jω_0}t}\)
  2. \(e^{jω_0t}\)
  3. \(\frac {e^{jω_0t}}{2\pi}\)
  4. \(2\pi e^{jω_0t}\)

Answer (Detailed Solution Below)

Option 3 : \(\frac {e^{jω_0t}}{2\pi}\)
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संकल्पना:

फॉरियर रूपांतरण के लिए समय-स्थानांतरण गुण:

यदि X(ω), x(t) का फॉरियर रूपांतरण है,

\(x\left( {t - {t_0}} \right) ↔ X\left( \omega \right){e^{ - j\omega {t_0}}}\)  ---(1)

फॉरियर रूपांतरण का द्विविधता गुण:

यदि X(ω), x(t) का फॉरियर रूपांतरण है, 

\(X\left( t \right) ↔ 2\pi x\left( { - \omega } \right)\)

गणना:

δ(t) का फॉरियर रूपांतरण = 1 

अब व्युत्क्रम फॉरियर रूपांतरण की परिभाषा से

\(\delta(\omega)\leftrightarrow \frac{1}{2\pi}\)

अब समीकरण (1) से समय-स्थानांतरण गुण का प्रयोग करने पर

\(\delta(\omega \ - \ \omega_o)\leftrightarrow\frac{1}{2\pi}e^{j\omega_ot}\)

अतः विकल्प (3) सही उत्तर है। 

Important Points

इकाई आवेग फलन:

एक निरंतर-समय वाले इकाई आवेश फलन δ(t), जिसे डिराक डेल्टा फलन भी कहा जाता है, को निम्न रूप में परिभाषित किया गया है:

δ (t) = ∞ , t = 0

= 0,  हालाँकि

इकाई आवेग फलन को ‘1’ की दृढ़ता के साथ एक तीर के निशान द्वारा दर्शाया गया है जो इसके क्षेत्रफल को दर्शाता है। 

F1 Tapesh Anil 20.01.21 D2

\(\mathop \smallint \limits_{ - \infty }^\infty δ \left( t \right)dt = 1\)

डेल्टा फलन का गुण:

शल्कन गुण:

\(δ \left( {at} \right) = \frac{1}{{\left| {at} \right|}}δ \left( t \right)\)

गुणन गुण:

X(t).δ(t – t0) = x(t0)δ(t – t0)

प्रतिचयन गुण:

\(\mathop \smallint \limits_{ - \infty }^\infty x\left( t \right)δ \left( {t - {t_0}} \right)dt = x\left( {{t_0}} \right)\)

महत्वपूर्ण समीकरण:

 X(t).δ(t) = x(0)δ(t)

\(\mathop \smallint \limits_{ - \infty }^\infty x\left( t \right)δ \left( t \right)dt = x\left( 0 \right)\)

 

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