Question
Download Solution PDFदी गई आकृति में, ABCD एक समांतर चतुर्भुज है जिसमें ∠DCB = 85° और ∠ADB = 55° है, तो ∠ABD बराबर है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
∠DCB = 85°
∠ADB = 55°
प्रयुक्त अवधारणा:
एक समांतर चतुर्भुज में विपरीत कोण समान होते हैं और विपरीत भुजाएँ समांतर होती हैं
त्रिभुज के सभी कोणों का योग 180° होता है
गणना:
समांतर चतुर्भुज के विपरीत कोण
⇒ ∠DCB = ∠DAB
⇒ ∠DAB = 85°
त्रिभुज के कोणों का योग = ∠ABD + ∠ADB + ∠DAB
⇒ ∠ABD + 55° + 85° = 180°
⇒ ∠ABD = 180° - 140°
⇒ ∠ABD = 40°
∴ ∠ABD का मान 40° है।
Last updated on Apr 30, 2025
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