Question
Download Solution PDF(1 + x)50 के प्रसार में x के विषम घातों के गुणांकों का योगफल क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFप्रयुक्त सूत्र:
(1 + x)n = [nC0 + nC1 x + nC2 x2 + … +nCn xn]
- C0 + C1 + C2 + … + Cn = 2n
- C0 + C2 + C4 + … = 2n-1
- C1 + C3 + C5 + … = 2n-1
गणना:
(1 + x)50 = [50C0 + 50C1 x + 50C2 x2 + … +50Cn x50] ----(1)
यहाँ, n = 50
उपरोक्त सूत्र का उपयोग करते हुए, गुणांक के विषम पदों का योग है
S = (50C1 + 50C3 + 50C5 + ……. + 50C49)
⇒ S = 250-1 = 249
∴ गुणांक के विषम पदों का योग = 249
Last updated on May 30, 2025
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