Question
Download Solution PDFएक विद्यालय में, 50% छात्र क्रिकेट खेलते हैं और 40% छात्र फुटबॉल खेलते हैं। यदि 10% छात्र दोनों खेल खेलते हैं, तो कितने प्रतिशत छात्र न तो क्रिकेट खेलते हैं और न ही फुटबॉल?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFगणना:
यदि A = क्रिकेट खेलने वाले विद्यार्थी है, B = फुटबॉल खेलने वाले विद्यार्थी है
⇒ n (A) = 50% और n (B) = 40%
⇒ n (A ∩ B) = 10%
⇒ n (A ∪ B) = n (A) + n (B) - n (A ∩ B) = 50 + 40 - 10 = 80%
जैसा कि हम जानते हैं (A ∪ B) ’ = A’ ∩ B’
⇒ n ( (A ∪ B) ’) =n (U) - n (A ∪ B) = 100 - 80 = 20% = n (A’ ∩ B’)Last updated on May 30, 2025
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