यदि (x - 1)2 + (y - 2)2 = (x – 1) (y - 2), जहाँ x और y पूर्णांक हैं, तो 2x + 3y का मान है:

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RRB ALP Electronics Mechanic 21 Jan 2019 Official Paper (Shift 1)
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  1. 5
  2. 8
  3. 11
  4. 7

Answer (Detailed Solution Below)

Option 2 : 8
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दिया गया है,

(x - 1)2 + (y - 2)2 = (x – 1) (y - 2)

गणना:

(x - 1)2 + (y - 2)2 = (x – 1) (y - 2)

यह x और y के सभी वास्तविक मानों के लिए हमेशा सत्य होगा।

तो, यदि x = 1

⇒ (1 - 1)2 + (y - 2)2 = (1 – 1) (y - 2)

⇒ (y - 2)2 = 0

⇒ y =  2

⇒ 2x + 3y = 2 × 1 + 3 × 2

⇒ 2x + 3y = 8

Alternate Method 

दिया गया है,

(x - 1)2 + (y - 2)2 = (x – 1) (y - 2)

अवधारणा:/सूत्र:

(x – y)2 = k2

(x – y) = k या (–k)

x = (k + y) या (y – k)

गणना:

(x -1)2 + (y - 2)2 = (x – 1) (y - 2)

लेते हैं,

⇒ (x – 1)2 = (x – 1) (y – 2)

⇒ (x – 1) = (y – 2)

⇒ x – y = -2 + 1

⇒ x – y = (-1)     ----(1)

लेते हैं,

⇒ (y – 2)2 = (x – 1) (y – 2)

⇒ (y – 2) = (x – 1)

⇒ x – y = -2 + 1

⇒ x – y = (-1)     ----(2)

मान लीजिये y = 2 और x = 1, तो

⇒ 1 – 2 = (-1)

(-1) = (-1) (संतुष्ट)

अब,

2x + 3y

⇒ 2 × 1 + 3 × 2

⇒ 2 + 6

⇒ 8

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