Question
Download Solution PDFयदि मेमोरी चिप का आकार 1024 × 4 है, तो 8 k मेमोरी को डिज़ाइन करने के लिए आवश्यक मेमोरी चिप्स की संख्या ___ है।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFमेमोरी का आकार = 8 k = 8 × 210 × 8 बिट
प्रत्येक मेमोरी चिप का आकार = 1024 × 4 = 210 × 4
आवश्यक मेमोरी चिप्स की संख्या = मेमोरी का आकार/प्रत्येक मेमोरी चिप का आकार
\( = \frac{{8 \times {2^{10}} \times 8}}{{{2^{10}} \times 4}} = 16\)
Last updated on Jul 2, 2025
-> ESE Mains 2025 exam date has been released. As per the schedule, UPSC IES Mains exam 2025 will be conducted on August 10.
-> UPSC ESE result 2025 has been released. Candidates can download the ESE prelims result PDF from here.
-> UPSC ESE admit card 2025 for the prelims exam has been released.
-> The UPSC IES Prelims 2025 will be held on 8th June 2025.
-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.
-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.