Question
Download Solution PDF50 ओम लक्षणिक प्रतिबाधा वाली एक संचरण रेखा पर विचार करें। इसे एक सिरे पर j 50 ओम से समाप्त किया जाता है। संचरण रेखा में इसके द्वारा उत्पन्न VSWR होगा
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
वोल्टेज अप्रगामी तरंग अनुपात (VSWR) को गणितीय रूप से इस प्रकार परिभाषित किया गया है:
\(VSWR = \frac{{\left( {1 + \left|\Gamma \right|} \right)}}{{\left( {1 - \left| \Gamma \right|} \right)}}\) ---(1)
Γ = परावर्तन गुणांक इस प्रकार दिया गया है:
\(\Gamma_L= \frac{{{Z_L} - {Z_o}}}{{{Z_L} + {Z_o}}}\)
ZL = भार प्रतिबाधा
Z0 = लक्षणिक प्रतिबाधा
अनुप्रयोग:
दिया गया है: Zo = 50 Ω और ZL = j50
परावर्तन गुणांक होगा:
\(\Gamma_L= \frac{{{Z_L} - {Z_o}}}{{{Z_L} + {Z_o}}}\)
\(\Gamma_L= \frac{{ j50 - 50}}{{j50 + 50}}\)
\(\Gamma_L = \frac{{ j-1}}{{j+1}}\)
\(\left| \Gamma \right| = \sqrt {\frac{{{{\left( {1} \right)}^2} + {{\left( {1} \right)}^2}}}{{{{\left( {1} \right)}^2} + {{\left( {1} \right)}^2}}}} \)
\(|\Gamma|= 1\)
अब, वोल्टेज अप्रगामी तरंग अनुपात होगा:
\(VSWR = \frac{{1 + 1}}{{1 - 1}}\)
VSWR = ∞
Last updated on Jan 11, 2024
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