Question
Download Solution PDFएक ऊष्मा इंजन 1500 kJ/मिनट की दर पर ऊष्मा प्राप्त करता है और 8.2 kW का आउटपुट प्रदान करता है, तो तापीय दक्षता क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
ऊष्मा इंजन की तापीय दक्षता
\({\eta _{thermal}} = \frac{{Power\;Output}}{{Heat\;Input}}\)
गणना:
दिया गया है:
ऊष्मा इनपुट = 1500 kJ/min = 25 kW, शक्ति आउटपुट = 8.2 kW
Last updated on Mar 27, 2025
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