For Spearman's rank correlation, if the correlation coefficient is 0.7 and  then the value of sample size 'n' is: 

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SSC CGL Tier-II (JSO) 2022 Official Paper (Held On: 4 March 2023)
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  1. 99
  2. 20
  3. 10
  4. 990

Answer (Detailed Solution Below)

Option 3 : 10
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SSC CGL Tier 1 2025 Full Test - 01
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Detailed Solution

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The correct answer is 10
Key Points

 The Spearman's rank correlation is formulated as: 

ρ = Spearman's rank correlation coefficient

di = different between the two ranks of each observation

n = number of observation
Given, ρ = 0.7 and 
Putting the given values into the formula, we get: 

or, 

or, 
Simplifying the equation we have, 
Now, following the method of trial and error, we get: 

  • n = 99 ⇒  ⇒ Violated
  • n = 20 ⇒  ⇒ Violated
  • n = 10 ⇒  ⇒ Satisfied 
  • n = 990 ⇒  ⇒ Violated

Hence, the required sample size is 10. 

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