Question
Download Solution PDFFor a binary phase-shift keying modulator with a carrier frequency of 70 MHz and input bit rate of 10 Mbps, the maximum Upper Side Frequency (USF) and minimum Lower Side Frequency (LSF) are respectively
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The spectrum of BPSK is represented as:
Max upper side frequency \(\left( {USBF} \right) = {f_c} + \frac{{{R_b}}}{2}\)
Minimum lower side freq. \(\left( {LSBF} \right) = {f_c} - \frac{{{R_b}}}{2}\)
Where,
fc = carrier frequency
Rb = Input but rate
Calculation:
Given:
Rb = 10 Mbps, fc = 70 MHz
Max upper side frequency will be:
\({f_c} + \frac{{{R_b}}}{2} = 70 + \frac{{10}}{2} = 75\;MHz\)
Min lower side frequency will be:
\({f_c} - \frac{{{R_b}}}{2} = 70 - \frac{{10}}{2} = 65\;MHz\)
Hence, the BPSK spectrum will be:
Last updated on Jul 2, 2025
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