Question
Download Solution PDFFind domain of the function \({\rm{f}}\left( {\rm{x}} \right) = {\rm{\;}}\frac{4}{{\sqrt {{\rm{x}} - 2} }}\).
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
1. Domain of a functions:
- The domain of a function is the set of all possible values of the independent variable. That is all the possible inputs for a function.
Calculation:
Observe that the given function is in the form of numerator and denominator. The function will be well defined for all non zero values of the denominator.
Therefore, \({\rm{x}} - 2{\rm{\;}} \ne 0\) that implies that \({\rm{x\;}} \ne 2\).
Similarly square root function is well defined for all non-negative values.
Therefore, \({\rm{x}} - 2 > 0\) that implies \({\rm{x}} > 2.\)
Thus, domain of the given function is \(\left( {2,{\rm{\;}}\infty } \right).\)
Last updated on Jun 18, 2025
->UPSC has extended the UPSC NDA 2 Registration Date till 20th June 2025.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.