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Considering 40 Ω as load resistance (which is connected between A and B). Norton's resistance of the circuit is equal to 6.67 Ω. Calculate Norton's resistance of the same circuit if 40 is replaced with 80 Ω.

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MPPGCL JE Electrical 28 April 2023 Shift 1 Official Paper
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  1. 7.67 Ω
  2. 13.67 Ω
  3. 6.67 Ω
  4. 4.67 Ω

Answer (Detailed Solution Below)

Option 3 : 6.67 Ω
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Detailed Solution

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Norton Theorem

Norton's theorem states that it is possible to simplify any linear circuit, into an equivalent circuit with a single current source and a parallel resistance.

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Explanation

Norton's resistance is calculated by opening the terminal. By opening the terminal, the Norton resistance for the circuit becomes independent of the resistance present at the AB terminal.

Hence, the Norton resistance for 80Ω will be the same as the 40Ω i.e. 6.67 Ω.

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