Consider the given Bode plot of a system and find the transfer function.

F1 Mrunal Engineering 03.10.2022 D5 V2

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UPPCL AE Electrical 2 April 2022 Official Paper (Shift 2)
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  1. K(sτa+1)(sτb+1)(sτ1+1)(sτ2+1)(sτ3+1)(sτ4+1)
  2. K(sτa+1)s(sτ1+1)(sτ2+1)(sτ3+1)(sτ4+1)
  3. K(sτa+1)(sτb+1)s(sτ1+1)(sτ2+1)(sτ3+1)(sτ4+1)
  4. K(sτb+1)s(sτ1+1)(sτ2+1)(sτ3+1)(sτ4+1)

Answer (Detailed Solution Below)

Option 3 : K(sτa+1)(sτb+1)s(sτ1+1)(sτ2+1)(sτ3+1)(sτ4+1)
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ST 1: UPPCL AE - Electric Circuits
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Detailed Solution

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Concept:

One pole provides a slope of -20 dB/decade.

One zero provides a slope of +20 dB/decade.

The frequencies where the bode plot changes slope are known as the cross-over frequencies.

Explanation:

The cross-over frequencies are: 1τ1,1τ2,1τa,1τb,1τ3 and 1τ4

The initial slope is -20 dB/decade, hence a pole at the origin is present.

1τ1

Addition of one pole (-20-20 = -40 dB/dec)

1τ2

Addition of one pole (-40-20 = -60 dB/dec)

1τa

Addition of one zero (-60+20 = -40 dB/dec)

1τb

Addition of one zero (-40+20 = -20 dB/dec)

1τ3

Addition of one pole (-20-20 = -40 dB/dec)

1τ4

Addition of one pole (-40-20 = -60 dB/dec)

Hence, the transfer function is:

T(s)=K(sτa+1)(sτb+1)s(sτ1+1)(sτ2+1)(sτ3+1)(sτ4+1)

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