Question
Download Solution PDFAnswer (Detailed Solution Below)
Option 3 : 1
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ST 1: B.Ed. Common Entrance (Teaching Aptitude)
15 Qs.
15 Marks
15 Mins
Detailed Solution
Download Solution PDFধারণা :
- cot A = 1/ tan A
- cos A = 1/ sec A
- sin A = cos (90° - A)
- cos2 A + sin2 A = 1
-
tan A = cot (90° - A)
গণনা :
⇒ cot 18° (cot 72° . cos2 22° + cot 72° . cos2 68°) (∵ cot A = 1/ tan A and cos A = 1/ sec A)
⇒ cot 18° [cot 72° (cos2 22° + cos2 68°)]
⇒ cot 18° . cot 72° (cos2 22° + sin2 22°) [∵ sin A = cos (90° - A)]
⇒ cot 18° . cot 72° (∵ cos2 A + sin2 A = 1)
⇒ cot 18° . tan 18° [∵ tan A = cot (90° - A)]
⇒ 1
সুতরাং,
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