An electric bulb of 40 W is connected to a power supply of 220 V. Calculate the resistance of the bulb and the units consumed if it is used for 24 hours.

  1. 1100 Ω, 0.96 Units
  2. 1110 Ω, 0.96 Units
  3. 1210 Ω, 0.96 Units
  4. 1260 Ω, 0.96 Units

Answer (Detailed Solution Below)

Option 3 : 1210 Ω, 0.96 Units
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Detailed Solution

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Concept:

Power: The rate of work done by electric energy is called power. It is denoted by P.

\(P = VI = \frac {V^2}{R} = I^2 R\)

  • The SI unit of power is the watt (W)
  • 1 Kilo-watt = 1000 Watt

1 unit of electric energy: When a one-kilowatt load works for 1 hour then the energy consumed is called 1 unit of electricity.

  • 1 Unit of electricity = 1 kWh = 1000 Watt-hour = 3.6 × 106 J

Calculation:

Given:

P = 40 W = 0.04 kW, V = 220 V, t = 24 hr

Using \(P = \frac {V^2}{R} \)

\(40 = \frac {220^2}{R} \)

R = 1210 Ω 

Now, the units consumed = P × t

= 0.04 × 24 

= 0.96 kWh = 0.96 Unit

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