A sum of money invested at simple interest triples itself in 18 years. Find in how many years will it become 19 times itself at the same rate of interest.

Question

Question

This question was previously asked in

OSSC CGL 2022 Official Paper (Held on: 18th Oct Shift 1)

Answer 1

Given:

Time = 18 years

A = 3P

Concept:

\(\frac {t1}{t2} = \frac {n1 - 1}{n2 - 1}\)

Where, t = time and n = times

Calculation:

⇒ \(\frac {18}{t2} = \frac {3 - 1}{19 - 1}\)

⇒ \(\frac {18}{t2} = \frac {2}{18}\)

⇒ \(\frac {18}{t2} = \frac {1}{9}\)

⇒ t2 = 162 years

∴ The required years will be 162 years.