A subject performs exercise of 5 minutes on Harvard step test. His recovery pulse count after exercise for 1 to \(1\frac{1}{2}\) minutes is 90, 2 to \(2\frac{1}{2}\) minutes is 65 and 3 to \(3\frac{1}{2}\) minutes is 45. The physical efficiency index of the subject is

The correct answer is 75.

Concept:

• The Physical Efficiency Index (PEI) of a subject in the Harvard Step Test can be calculated based on their pulse rate recovery during the recovery period.
• The Harvard Step Test is a submaximal exercise test that measures cardiovascular fitness and endurance.
• The PEI can provide an estimate of an individual's aerobic fitness level.

Explanation:

\(Fitness\ Index = {(100*test \ duration\ in \ seconds) \over (2*sum\ of\ heart \ beats \ in \ the\ recovery\ periods) }\)

sum of heart beats in the recovery periods= 90+65+45

                        \(= {(100*300) \over (2*200)} \)  \(= {30,000\over 400}\)  \(= 75\)

So, the PEI of the subject in this case would be 75.