A student takes a quiz consisting of 5 multiple choice questions. Each question has 4 possible answers. If a student is guessing the answer at random and answer to different are independent, then the probability of atleast one correct answer is

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NIMCET 2014 Official Paper
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  1. 0.237
  2. 0.00076
  3. 0.7627
  4. 1

Answer (Detailed Solution Below)

Option 3 : 0.7627
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NIMCET 2020 Official Paper
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120 Questions 480 Marks 120 Mins

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Concept: 

If there can be only 2 cases of true and false, then:

Probability of r true cases out of n (≥ r) P(x = r) = nCr prq(n-r) 

where p is the probability of case being true and q is probability of case being false

Note: p and q are ≤ 1

 

Calculation:

The probability of correct answer p\(\rm 1\over 4\) = 0.25

The probability of wrong answer q = \(\rm 3\over 4\) = 0.75

Total questions n = 5

Probability of atleast one correct answer (x ≥ 1):

P(x ≥ 1) = 1 - P(x = 0)

⇒ P(x ≥ 1) = 1 - 5C0 p0q5

⇒ P(x ≥ 1) = 1 - (0.75)5 

⇒ P(x ≥ 1) = 1 - 0.2373

⇒ P(x ≥ 1) \(\boldsymbol{\rm \approx}\) 0.7627

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