A can hit a target 5 times in 6 shots, B can hit 4 times in 5 shots and C can hit 3 times in 4 shots. What is the probability that A and C may hit but B may lose?

Question

Question

This question was previously asked in

NDA-II 2024 (Maths) Official Paper (Held On: 01 Sept, 2024)

Answer 1

Explanation:

Here, P(A) = 5/6 , P(B) = 4/5 , P(C) = 3/4

Also

P(B) = \(1 - \frac{4}{5} = \frac{1}{5}\)

Now

⇒ \(P ( A\cap \overline{B} \cap C) = P(A).P(B).P(C)\)

= \(\frac{5}{6}\times \frac{1}{5}\times \frac{3}{4} = \frac{1}{8}\)

∴ Option (a) is correct.

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