Question
Download Solution PDFA DC shunt motor runs at 500 rpm at 220 V. A resistance of 9 Ω is added in series with armature for speed control. The armature resistance is 1 Ω. The current to stall the motor will be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
For stalling back emf of DC motor
Eb = V - IaRa = 0
Where,
N is the speed of the DC shunt motor
Eb is back emf
φ is flux per pole
Calculation:
Given
Terminal voltage (V) = 220 V
Total armature resistance (Ra) = 9+1= 10 Ω
For stalling
V - IaRa = 0
⇒ 220 -Ia × 10 = 0
\(\Rightarrow {I_{{a_{stalling}}}} = 22\;A\)
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