Question
Download Solution PDFA cylinder of radius 2.8 cm and height 8 cm is removed from a solid cone of radius 5.6 cm and height 24 cm. What is the volume (in cm3) of the remaining part of the cone? (Takе π = \(\frac{22}{7}\))
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Cylinder:
Radius (rc) = 2.8 cm, Height (hc) = 8 cm
Cone:
Radius (rco) = 5.6 cm, Height (hco) = 24 cm
Formula used:
Volume of cylinder = πrc2hc
Volume of cone = (1/3)πrco2hco
Calculation:
Volume of cylinder:
Vc = (22/7) × (2.8)2 × 8 = (22/7) × 7.84 × 8
Vc = 197.12 cm3
Volume of cone:
Vco = (1/3) × (22/7) × (5.6)2 × 24 = (1/3) × (22/7) × 31.36 × 24
⇒ (22/7) × 31.36 × 8
Vco = 788.48 cm3
Volume of remaining part = Volume of cone - Volume of cylinder
Vremaining = Vco - Vc
Vremaining = 788.48 - 197.12 = 591.36 cm3
∴ The volume of the remaining part of the cone is 591.36 cm3.
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