Question
Download Solution PDFA body move from rest with a constant acceleration of 5 m/sec2. The distance cover in 5 sec is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Equation of motion:
It is defined as equations that describe the behaviour of a physical system in terms of its motion as a function of time.
There are three equation of motions:
- v = u + at
- \(s = ut + \frac 12at^2\)
- v2 = u2 + 2as
where u = initial velocity, v = final velocity, a = acceleration, s = displacement, t = time
Calculation:
Given:
u = 0 m/s, a = 5 m/s2, t = 5 s
\(s = ut + \frac 12at^2\)
\(s = 0\times t + \frac 12at^2\)
\(s = \frac 12at^2 = \frac 12 \times 5\times 5^2= 62.5 ~m\)
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