A 729 ml of a mixture contains milk and water in the ratio of 7 : 2. How much more water is to be added to get a new mixture containing milk and water in the ratio of 7 : 3?

Question

Question

This question was previously asked in

UGC NET Paper 1: Held on 14th Oct 2022 Shift 2

Answer 1

Concept Used:

The ratio is the relation among two or more numbers, which tells how much one number is bigger than the others.

To solve the questions based on ratio, we use to assume a variable for the shared part among quantities.

Calculation:

Let the amount of milk is 7x while the amount of water is 2x in the mixture. Now, we have a total of 729 mL of the mixture. Thus,

⇒ 7x + 2x = 729

⇒ 9x = 729

⇒ x = 729/9

⇒ x = 81
Thus, the amount of milk

⇒ 7x = 7 × 81

⇒ 7x = 567 mL

Amount of water

⇒ 2x = 2 × 81

⇒ 2x = 162 mL

Now, the new mixture has a ratio of 7:3.

For this, the amount of milk will be 7x and the amount of water is 3x.

Here, the quantity of milk is the same while the quantity of water is increasing. This increased quantity is,

⇒ 3x − 2x = x

⇒ 3x − 2x = 81 mL

So, a total of 81 mL water needs to be added to get a new mixture containing milk and water in the ratio of 7 : 3.

Hence, the correct option is 1.

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