A 12 F capacitor is connected in parallel with a 6 F capacitor. Find the equivalent capacitance of the parallel combination.

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MPPGCL JE Electrical 28 April 2023 Shift 2 Official Paper
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  1. 18 F
  2. 6 F
  3. 4 F
  4. 9 F

Answer (Detailed Solution Below)

Option 1 : 18 F
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MPPGCL JE Electrical Full Test 1
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Detailed Solution

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Concept

Series connection of capacitors:

When 'n' capacitors are connected in series, the equivalent capacitance is given by:

\({1\over C_{eq}}={1\over C_{1}}+{1\over C_{2}}........{1\over C_{n}}\)

If all capacitors are equal, then:

\(C_{eq}={C\over n}\)

Parallel connection of capacitors:

When 'n' capacitors are connected in parallel, the equivalent capacitance is given by:

\(C_{eq}=C_1+C_2.......C_n\)

If all capacitors are equal, then:

\(C_{eq}=nC\)

Calculation

Given, C1 = 12 F and C2 = 6 F

The equivalent capacitance of the parallel combination is:

\(C_{eq}=12\space F\space + \space 6\space F\)

\(C_{eq}=18\space F\space \)

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