Question
Download Solution PDF(120% of 675) + 92 = (? % of 1240) + 716
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFormula Used:
X% = X/100
Calculation:
(120% of 675) + 92 = (? % of 1240) + 716
⇒ \(\frac{120}{100} \)× 675 + 92 = \(\frac{?}{100} \)× 1240 + 716
⇒ 810 + 92 = 12.4 × ? + 716
⇒ 902 - 716 = 12.4 × ?
⇒ 186/12.4 = ? = 15
∴ The correct answer is 15
Last updated on Mar 19, 2025
-> CISF Constable Tradesman Recruitment 2025 Detailed Notification has been released.
-> According to the notice, a total number of 1161 Vacancies have been announced for various posts/trade under CISF Tradesman Recruitment 2025.
-> Interested candidates can apply online from 5th March to 3rd April 2025.
-> Candidates should be 10th Passed + ITI to be eligible for the examination process.
-> Candidates who want to score high and crack the exam must go through the CISF Constable Tradesman previous year papers to understand the trend of the questions for the exam.