Pumps MCQ Quiz - Objective Question with Answer for Pumps - Download Free PDF
Last updated on Jun 23, 2025
Latest Pumps MCQ Objective Questions
Pumps Question 1:
Which factor does NOT directly affect the power required to drive a centrifugal pump?
Answer (Detailed Solution Below)
Pumps Question 1 Detailed Solution
Explanation:
Centrifugal Pump
- A centrifugal pump is a mechanical device designed to move fluid by converting rotational kinetic energy into hydrodynamic energy of the fluid flow. The power required to drive a centrifugal pump depends on several factors related to the fluid properties and operating conditions. These factors include flow rate, fluid density, fluid viscosity, and total head (which includes suction and delivery heads). However, atmospheric pressure does not directly influence the power requirement for driving the pump under standard operating conditions. Below, we will explore why this is the case and analyze the other options in detail.
Correct Option Analysis:
The correct option is:
Option 1: Atmospheric Pressure
Atmospheric pressure does not directly affect the power required to drive a centrifugal pump. Here's why:
The power required to drive a centrifugal pump (often referred to as "brake horsepower" or BHP) is calculated using the following formula:
BHP = (Flow Rate × Total Head × Fluid Density) / (3960 × Pump Efficiency)
- From this equation, it is evident that the power requirement is directly proportional to the flow rate, total head, and fluid density, while inversely proportional to the pump efficiency. Atmospheric pressure does not appear in this formula because it is typically a constant factor that affects both sides of the pump system equally (i.e., the suction side and the discharge side). Unless the system involves conditions where atmospheric pressure significantly varies (e.g., high-altitude operation or vacuum systems), it does not play a direct role in determining the power required to drive the pump.
In most practical applications, centrifugal pumps are designed to operate under standard atmospheric conditions, and any minor variations in atmospheric pressure are negligible in terms of their impact on pump power requirements. Therefore, atmospheric pressure is not a direct factor in the calculation of pump power.
Pumps Question 2:
A centrifugal pump has a hydraulic power output of 10 kW and consumes 15 kW of mechanical power. Calculate its overall efficiency.
Answer (Detailed Solution Below)
Pumps Question 2 Detailed Solution
Explanation:
Overall Efficiency of a Centrifugal Pump:
A centrifugal pump operates by converting mechanical energy into hydraulic energy. The overall efficiency of the pump is determined by comparing the hydraulic power output to the mechanical power input. The formula for efficiency is expressed as:
Efficiency (η) = (Hydraulic Power Output / Mechanical Power Input) × 100
In this case, the hydraulic power output is 10 kW, and the mechanical power input is 15 kW. Substituting these values into the formula:
η = (10 / 15) × 100
Performing the calculation:
η = 0.6667 × 100
η = 66.67%
Pumps Question 3:
Compared to a single volute casing, a double volute casing with a vaned diffuser generally provides:
Answer (Detailed Solution Below)
Pumps Question 3 Detailed Solution
Explanation:
Double Volute Casing with Vaned Diffuser
- A double volute casing with a vaned diffuser is a specific design in centrifugal pumps that enhances hydraulic performance and efficiency. The double volute casing is designed to reduce radial forces acting on the impeller, leading to a balanced operation and improved efficiency. The vaned diffuser, on the other hand, helps to convert the velocity energy of the fluid into pressure energy more effectively, minimizing energy losses and improving the overall hydraulic performance.
- In comparison to single volute casing designs, the double volute casing provides additional benefits. The double volute casing divides the flow into two symmetrical paths, which helps to balance the pressure around the impeller. This results in reduced radial forces acting on the impeller, leading to less vibration, lower wear, and enhanced longevity of pump components. The incorporation of a vaned diffuser further contributes to improved efficiency by streamlining the flow paths and reducing turbulence.
- The double volute casing, combined with a vaned diffuser, offers superior hydraulic performance and efficiency compared to a single volute casing. The double volute design balances the radial forces, which reduces the mechanical stresses on the pump components. This balance minimizes vibration and wear, leading to smoother operation and longer service life.
- The vaned diffuser contributes significantly to hydraulic performance by aiding the efficient conversion of velocity energy into pressure energy. This results in reduced turbulence and energy losses in the flow path, increasing the pump's overall efficiency. Pumps with double volute casings and vaned diffusers are particularly advantageous in applications requiring high efficiency and reliability, such as in industrial processes, water treatment, and power generation.
Additional Information
Important points to note:
- Reduced Radial Forces: The double volute casing design splits the flow into two symmetrical paths, reducing the radial forces on the impeller. This results in smoother operation and less wear on pump components.
- Improved Efficiency: The vaned diffuser minimizes energy losses by converting velocity energy into pressure energy efficiently. This enhances the overall hydraulic performance.
- Applications: Double volute casings with vaned diffusers are widely used in industries where high efficiency and reliability are critical, such as chemical processing, water treatment, and power generation.
- Durability: Reduced mechanical stresses and wear lead to longer service life and lower maintenance requirements for the pump.
Pumps Question 4:
In a radial flow pump, the fluid primarily flows:
Answer (Detailed Solution Below)
Pumps Question 4 Detailed Solution
Explanation:
Radial Flow Pumps:
- Radial flow pumps are a type of centrifugal pump where the fluid enters axially into the impeller but exits radially, perpendicular to the pump shaft. These pumps are designed to develop high pressures with relatively low flow rates, making them suitable for applications where a significant pressure head is required.
Working Principle: In a radial flow pump, fluid is drawn into the center of the impeller along its axis (axial direction). The rotating impeller imparts kinetic energy to the fluid, converting it into pressure energy as the fluid moves outward in a radial direction. The fluid exits the pump casing at a 90-degree angle to the shaft.
Advantages:
- Capable of generating high pressures, making them ideal for applications requiring a large pressure head.
- Compact design and relatively easy to maintain.
- Well-suited for handling clean liquids with low viscosity.
Disadvantages:
- Limited flow rate capabilities compared to axial flow pumps.
- Not suitable for handling large volumes of fluid or highly viscous liquids.
Applications: Radial flow pumps are commonly used in industries such as water supply, chemical processing, boiler feed applications, and irrigation systems where high pressure and low flow rates are required.
Pumps Question 5:
The manometric efficiency in a pump is the ratio of:
Answer (Detailed Solution Below)
Pumps Question 5 Detailed Solution
Explanation:
Manometric Efficiency:
- The manometric efficiency of a centrifugal pump is defined as the ratio of the manometric head to the head imparted by the impeller.
- Manometric head is the actual head against which a centrifugal pump works.
To understand this better, let's break down the terms:
Manometric Head:
- It is the total head developed by the pump minus the losses in the pump.
- It is essentially the head that is effectively used to lift the fluid.
Head Imparted by the Impeller:
- This is the theoretical head that the impeller would impart to the fluid if there were no losses.
The formula for manometric efficiency (ηm) is given by:
ηm = (Manometric Head) / (Head Imparted by the Impeller)
Important Points
- The manometric efficiency is always less than 100% due to losses in the pump.
- Higher manometric efficiency indicates a more effective pump with fewer losses.
Additional Information
Other efficiencies related to centrifugal pumps include:
(1) Volumetric Efficiency:
- It is the ratio of the actual discharge to the theoretical discharge.
- It accounts for the leakage losses within the pump.
(2) Mechanical Efficiency:
- It is the ratio of the power available at the impeller to the power at the shaft.
- It accounts for the mechanical losses in the pump.
(3) Overall Efficiency:
- It is the product of volumetric efficiency, mechanical efficiency, and manometric efficiency.
Top Pumps MCQ Objective Questions
Which of the following is a positive displacement pump?
Answer (Detailed Solution Below)
Pumps Question 6 Detailed Solution
Download Solution PDFExplanation:
Positive displacement pump:
- Positive displacement pumps are those pumps in which the liquid is sucked and then it is pushed or displaced to the thrust exerted on it by a moving member, which results in lifting the liquid to the required height.
- Reciprocating pump, Vane pump, Lobe pump are the examples of positive displacement pump whereas the centrifugal pump is the non-positive displacement pump.
The specific speed (Ns) of the pump is given by the expression
Answer (Detailed Solution Below)
Pumps Question 7 Detailed Solution
Download Solution PDFExplanation:
Specific speed:
- It is defined as the speed of a geometrically similar pump that would deliver one cubic meter of liquid per second against the head of one meter.
- It is used to compare the performances of 2 different pumps.
- Its dimension is M0L3/4T-3/2 and given by the formula and is given by
\(N_{s}=\frac{N\sqrt{Q}}{H_{m}^{3/4}}\)
Where NS = Specific speed, Q = Discharge, H = Head under which the pump is working, N = Speed at the pump is working.
Additional Information
(specific speed for turbines) = \({{\rm{N}}_{\rm{s}}} = \frac{{{\rm{N}}{\sqrt{P}}}}{{{{\rm{H_m}}^{5/4}}}}\)
The overall efficiency of a centrifugal pump when head is 25 m, discharge = 0.04 m3/s and output power p = 16 kW (take g = 10 m/s2? and ρ = 1000) is
Answer (Detailed Solution Below)
Pumps Question 8 Detailed Solution
Download Solution PDFExplanation:
Overall Efficiency (η): It is defined as a ratio of the power output of the pump to the power input to the pump.
The overall efficiency of the pump will be given as,
\({{\rm{\eta }}_{\rm{}}} = \frac{{{\rm{water\;power}}}}{{{\rm{shaft\;power\;}}}} = \frac{{{\rm{\omega QH}}}}{{\rm{P}}}\)
\(P = \frac{{{\bf{\omega QH}}\;}}{{{\eta }}}\)
Calculation:
\(\eta = \frac{{{\bf{\rho g QH}}\;}}{{{P }}} = \frac{{{\bf{1000\times10\times0.04\times25}}\;}}{{{16000}}}=0.625\)
Additional Information
Manometric Efficiency (ηman): It is the ratio of the manometric head to head imparted by the impeller to the water.
\({\eta _{man}} = \frac{{{H_m}}}{{\frac{{{V_{w2}}{u_2}}}{g}}} = \frac{{g{H_m}}}{{{V_{w2}}{u_2}}}\)
Mechanical Efficiency (ηm): It is the ratio of the power available at the impeller to the power at the shaft of the centrifugal pump.
\({\eta _m} = \frac{{{\rm{Power\;at\;the\;impeller}}}}{{{\rm{Power\;at\;the\;shaft}}}} = \frac{{\frac{W}{g}\left( {\frac{{{V_{w2}}{u_2}}}{{1000}}} \right)}}{{{\rm{SP}}}}\)
For the operating point of the pump, a system characteristic between the head required ‘H’ and the discharge to be maintained ‘Q’ is generally expressed as
Answer (Detailed Solution Below)
Pumps Question 9 Detailed Solution
Download Solution PDFConcept:
Before manufacturing the large-sized pumps, their models which are in complete similarity with the actual pumps (also called prototypes) are made. Tests are conducted on the models and the performance of the prototype is predicted. The complete similarity between the model and actual will exist if the following condition is satisfied.
I)\(\left ( \frac{\sqrt{H}}{DN} \right )_m=\left ( \frac{\sqrt{H}}{DN} \right )_p\;\;\;\;(1)\)
II) \(\left ( \frac{Q}{D^3N} \right )_m=\left ( \frac{Q}{D^3N} \right )_p\;\;\;\;\;(2)\)
III) \(\left ( \frac{P}{D^5{N^3}} \right )_m=\left ( \frac{P}{D^5{N^3}} \right )_p\;\;\;\;\;(3)\)
From (1)
\(\sqrt{H}∝\;N\)
From (2)
Q ∝ N
Combining (1) and (2)
\(\sqrt{H}∝\;Q\)
∴ H ∝ Q2
∴ the head 'H' varies with the square of discharge 'Q'
The relation between head 'H' and discharge 'Q' can be better understood with the Operating characteristic curve as shown in the figure which gives the relation between the manometric head (H), power (P) and efficiency (η) with respect to the discharge when the speed (N) is kept constant.
A centrifugal pump acts as a reverse of :
Answer (Detailed Solution Below)
Pumps Question 10 Detailed Solution
Download Solution PDFExplanation:
- The centrifugal pump acts as a reverse of an inward radial flow reaction turbine.
- This means that the flow in centrifugal pumps is in the radial outward direction.
- The centrifugal pump works on the principle of forced vortex flow which means that when a certain mass of liquid is rotated by an external torque, the rise in pressure head of the rotating liquid takes place.
- In a centrifugal pump casing, the flow of water leaving the impeller is a free vortex.
The flow in volute casing outside the rotating impeller of a centrifugal pump is:
Answer (Detailed Solution Below)
Pumps Question 11 Detailed Solution
Download Solution PDFExplanation:
Centrifugal pump works on the principle of force vortex. Where external torque is provided to the impeller by the means of the prime mover.
In a pump, there are two important parts, first is the impeller which creates velocity through rotation. And the second is the casing which converts this velocity into pressure by the change in the area.
When fluid is inside the impeller, then the speed of the fluid experience a rotational motion because of the torque provided by the prime mover, and flow is characterized as a forced vortex flow. When the fluid comes out from the rotating impeller at that time also fluid has a vortex motion because of the inertia of the fluid. But since the external torque is absent outside the casing therefore it becomes free vortex flow.
Additional Information
There are two types of casing generally available for the centrifugal pump.
1.Volute casing:
In volute casing area gradually increase as you can see in the above figure. Because of the gradual increase in the area the velocity decreases and pressure increases.
2.Diffuser casing:
In diffuser casing impeller periphery is designed in such a way that its area gradually increases which promotes the rise in the pressure at the expense of the velocity.
A centrifugal pump having an impeller diameter of 127 mm, delivers a power of 12 hp. If the impeller diameter is changed to 254 mm, what is the power, if other parameters are kept constant?
Answer (Detailed Solution Below)
Pumps Question 12 Detailed Solution
Download Solution PDFConcept:
As per the affinity law, the relationship between the power and diameter of the impeller is given by:
\(p\propto~D^3\)
Where P is shaft power, D is the diameter of the impeller,
Calculation:
Given:
P1 = 12 hp, D1 = 127 mm, D2 = 254 mm
In the given question it is said that the only diameter is changed and other parameters are constant then
\(\frac{P_2}{P_1}=(\frac{D_2}{D_1})^3\)
\(\frac{P_2}{12}=(\frac{254}{127})^3\)
\(\Rightarrow {P_2} = {\left( {\frac{{254}}{{127}}} \right)^3} × 12 = {2^3} × 12\;hp = 96\;hp\)
Centrifugal pumps dealing with muds have an impeller of the type
Answer (Detailed Solution Below)
Pumps Question 13 Detailed Solution
Download Solution PDFExplanation:
Closed impellers (Two-sides shrouded):
- In the closed or shrouded impellers, the vanes are covered with shrouds (side plates) on both sides
- The back shroud is mounted into the shaft and the front shroud is coupled by the vanes
- This ensures full-capacity operation with high efficiency for a prolonged running period
- This type of impeller is meant to pump only clear water, hot water and acids
Semi-open impeller (One-side shrouded):
- It has a plate (shroud) only on the backside
- The design is adapted to industrial pump problems which require a rugged pump to handle liquids containing fibrous material such as paper pulp, sugar molasses and sewage water etc.
Open impeller:
- In open impeller, no shroud or plate is provided on either side i.e. the vanes are open on both sides
- Such pumps are used where the pump has a very rough duty to perform i.e. to handle abrasive liquids such as a mixture of water, sand, pebbles, muds and clay, wherein the solid contents may be as high as 25%.
Thus, centrifugal pumps dealing with muds have an open impeller.
The overall efficiency of a centrifugal pump is:
Answer (Detailed Solution Below)
Pumps Question 14 Detailed Solution
Download Solution PDFExplanation:
In the case of a centrifugal pump, the power is decreasing from the shaft of the pump to the impeller and then from the impeller to the water. The following are the important efficiencies of a centrifugal pump:
- Manometric Efficiency (ηman): It is the ratio of the manometric head to head imparted by the impeller to the water.
\({\eta _{man}} = \frac{{{H_m}}}{{\frac{{{V_{w2}}{u_2}}}{g}}} = \frac{{g{H_m}}}{{{V_{w2}}{u_2}}}\)
- Mechanical Efficiency (ηm): It is the ratio of the power available at the impeller to the power at the shaft of the centrifugal pump.
\({\eta _m} = \frac{{{\rm{Power\;at\;the\;impeller}}}}{{{\rm{Power\;at\;the\;shaft}}}} = \frac{{\frac{W}{g}\left( {\frac{{{V_{w2}}{u_2}}}{{1000}}} \right)}}{{{\rm{SP}}}}\)
- Overall Efficiency (ηo): It is defined as a ratio of the power output of the pump to the power input to the pump.
When two centrifugal pumps are operated in series, the discharge
Answer (Detailed Solution Below)
Pumps Question 15 Detailed Solution
Download Solution PDFConcept:
Centrifugal Pump:
Centrifugal pumps are used to transport fluids by the conversion of rotational kinetic energy to the hydrodynamic energy of the fluid flow. The rotational energy typically comes from an engine or electric motor.
Operation of two Identical Pumps in Series:- The pressure in the rising main increases, it becomes almost double and the discharge remains constant.
- Head is also increased at a constant flow rate.
Important Points
Pumps in parallel: