Percentage MCQ Quiz - Objective Question with Answer for Percentage - Download Free PDF

Given:

If A is 20% of C and B is 25% of C.

Concept:

The x % of a value A is 

Solution:

Let the value of C be X

A = 20% of X = X/5

B = 25% of X = X/4

The percent of B that A is,

[ (X/5) / (X/4) ] x 100 = 80%

Hence, option 2 is correct.

Given:

a% of a + b% of b = 2% of ab

Calculation:

a% of a + b% of b = 2% of ab

⇒ a% × a + b% × b = 2% × ab

⇒ a² + b² = 2ab

⇒ a2 + b2 - 2ab = 0

⇒ (a - b)² = 0

So, a = b

According to the question,

⇒ x% of 2a = 3b

⇒ x% × 2a = 3a    (a = b)

⇒ x =  × 100 = 150%

Given:

Percentage = 22¹⁄₂%
Number = 400

Formula used:

Percentage of a number = (Percentage × Number) ÷ 100

Calculation:

22¹⁄₂% = 45⁄2 %

⇒ (45/2 × 400) ÷ 100

⇒ (18000 / 2) ÷ 100 = 9000 /100 = 90

∴ Final Answer = 90

Given:

20% of (1)/(3) = ?

Formula Used:

20% of a number = (20 / 100) × number

Calculation:

20% of (1)/(3) = (20 / 100) × (1)/(3)

⇒ 20 × (1)/(3) / 100

⇒ (20 × 1) / (3 × 100)

⇒ 20 / 300

⇒ 1 / 15

Given:

45% of 450

Formula used:

Percentage of a number = (Percentage × Number) / 100

Calculation:

45% of 450 = (45 × 450) / 100

⇒ (45 × 450) / 100

⇒ 202.5

∴ The correct answer is option (4).

Given:

P is 40% less than Q.

Shortcut Trick

40% = 2/5

So, Q is 2/(5-2) × 100 = 2/3 × 100 = 66.66% more than P.

∴ Q is 66.66% more than P.

Calculation:

Let, Q = 100y

So, P = 100y × (100 - 40)/100 = 100y × 60/100 = 60y

Now,

(Q – P)/P × 100 = 40y/60y × 100  = 66.66%

∴ Q is 66.66% more than P.

Additional Information

If A is 20% less than B,

So,

B is 20/(100 - 20) × 100 = 20/80 × 100 = 25% more than A

Similarly,

If B is 25% more than A,

So,

A is 25/(100 + 25) × 100 = 25/125 × 100 = 20% less than B.

Given:

200% of k - (k + 2)% of 50 = k

Formula used:

A% of B = (A/100) × B

Calculation:

⇒ 200% of k - (k + 2)% of 50 = k

⇒ (200/100) × k - (k + 2)/100 × 50 = k

⇒ 2k - 0.5(k + 2) = k

⇒ 2k - 0.5k - 1 = k

⇒ 1.5k - 1 = k

⇒ 1.5k - k = 1

⇒ 0.5k = 1

⇒ k = 1/0.5 = 2

Suppose the initial price = Rs. x per kg

Suppose the family spends Rs. 100 initially and this comes down to Rs. 93;

∴ [93/0.75x] – [100/x] = 12

⇒ 124/x – 100/x = 12

⇒ 24/x = 12

⇒ x = 2

∴ Increased consumption = 100/2 + 12 = 62 kg

Formula Used:

X% = X/100

Calculation:

(120% of 675) + 92 = (? % of 1240) + 716

⇒ × 675 + 92 = × 1240 + 716

⇒ 810 + 92 = 12.4 × ? + 716

⇒ 902 - 716 = 12.4 × ?

⇒ 186/12.4 = ? = 15

∴ The correct answer is 15

Formula Used:

X% = X/100

Calculation:

⇒ 980 of 12% = 

⇒ 227 of 30% = 

⇒ 117.6 - = 68.1

⇒ 117.6 - 68.1 = 

⇒  = ? = 11

∴ The correct answer is 11.

Solution:

75% of 480 + 48% of 750

⇒ (75/100) × 480 + (48/100) × 750

⇒ (3/4) × 480 + (12/25) × 750

⇒ 3 × 120 + 12 × 30

⇒ 360 + 360

⇒ 720

Given:

80% of A = 50% of B and B = x% of A

Calculation:

80% of A = 50% of B.

⇒  A =  B

⇒ 8A = 5B

⇒ 

∴ B =  = 160 

So, the value of x is 160.

Given:

20% of (x + y) = 25% of (x - y)

Formula used:

Percentage = (Obtained value/Total value) × 100

Calculation:

20% of (x + y) = 25% of (x - y)

⇒ 20(x + y) = 25(x - y)

⇒ 20x + 20y = 25x - 25y

⇒ 20y + 25y = 25x - 20x

⇒ 45y = 5x

⇒ x = 9y

Now, Percentage = (Obtained value/Total value) × 100

⇒ (x/y) × 100

⇒ (9y/y) × 100 

⇒ 900%

Follow the BODMAS rule to solve this question, as per the order given below, 

The given expression is,

60% of 80 ÷ 16 × 30% of 70 = ?

⇒ 48 ÷​ 16 ×​ 21 = ?

⇒ 3 ×​ 21 = ?​

⇒ ? = 63

∴ The value of ? is 63

Given:

The number = 2 × 10⁶

Calculation:

10⁶ = (10²)³

⇒ 100³

According to the question,

Required number = 2 × 1003 × 

⇒ 2 × 100 × 100 × 100 × 

⇒ 2 × 12 × 4 × 7

⇒ 672

∴ Required answer is 672.