P-Type Semiconductor MCQ Quiz - Objective Question with Answer for P-Type Semiconductor - Download Free PDF
Last updated on Jun 11, 2025
Latest P-Type Semiconductor MCQ Objective Questions
P-Type Semiconductor Question 1:
Which one among these is an example for trivalent impurity?
Answer (Detailed Solution Below)
P-Type Semiconductor Question 1 Detailed Solution
Trivalent Impurities in Semiconductors
Definition: Trivalent impurities are elements from group III of the periodic table that have three valence electrons. These impurities are introduced into an intrinsic semiconductor (pure semiconductor) to create a p-type semiconductor. When a trivalent impurity is added to a semiconductor, it creates "holes" (positive charge carriers), making the semiconductor conducive to electrical current primarily through hole movement.
Working Principle: In a pure semiconductor like silicon or germanium, each atom forms covalent bonds with four neighboring atoms. When a trivalent impurity (e.g., gallium) is added, it has only three valence electrons, which are insufficient to form four covalent bonds. The absence of the fourth electron creates a "hole" in the crystal lattice. This hole acts as a positive charge carrier, and the movement of these holes constitutes electric current in a p-type semiconductor.
Examples of Trivalent Impurities:
- Gallium (Ga): A commonly used trivalent impurity for doping semiconductors to create p-type materials.
- Boron (B): Another widely used trivalent impurity for the same purpose.
- Indium (In): Occasionally used for specific semiconductor applications.
Advantages of Doping with Trivalent Impurities:
- Increases the conductivity of the semiconductor by providing positive charge carriers.
- Enables the creation of p-n junctions, which are the basis of many electronic devices like diodes and transistors.
- Facilitates the customization of semiconductor properties for specific applications.
Correct Option Analysis:
The correct option is:
Option 3: Gallium
Gallium is a trivalent impurity, meaning it has three valence electrons. When introduced into a semiconductor, it creates holes by leaving a bond incomplete, which facilitates the formation of a p-type semiconductor. This is a classic example of a trivalent impurity used for doping semiconductors.
Additional Information
To further understand the analysis, let’s evaluate the other options:
Option 1: Phosphorus
Phosphorus is a pentavalent impurity, meaning it has five valence electrons. When added to a semiconductor, it donates an extra electron, creating an n-type semiconductor. This makes phosphorus unsuitable as a trivalent impurity.
Option 2: Antimony
Antimony is also a pentavalent impurity. Like phosphorus, it donates an extra electron when introduced into a semiconductor, leading to the formation of an n-type semiconductor. Therefore, it cannot be classified as a trivalent impurity.
Option 4: Arsenic
Arsenic is another pentavalent impurity. It behaves similarly to phosphorus and antimony by contributing an extra electron to the semiconductor lattice, creating an n-type semiconductor. It is not a trivalent impurity.
Option 5: None
This option is incorrect because Gallium (Option 3) is indeed a valid example of a trivalent impurity, as explained above.
Conclusion:
Among the options provided, Gallium is the correct example of a trivalent impurity. Trivalent impurities like Gallium play a crucial role in the semiconductor industry by enabling the creation of p-type semiconductors. Understanding the behavior of trivalent and pentavalent impurities is essential for designing and optimizing electronic devices such as diodes, transistors, and integrated circuits.
P-Type Semiconductor Question 2:
The resistivity of Si at 300K is 3.16 × 103 ohm-m. The mobility of electrons and holes in Si are 0.14 m2/V-sec and 0.06 m2/V-sec respectively. The intrinsic carrier density is:
Answer (Detailed Solution Below)
P-Type Semiconductor Question 2 Detailed Solution
Concept:
σ = q × nᵢ × (μₑ + μₕ)
- Intrinsic carrier density (nᵢ) in a semiconductor is related to resistivity and carrier mobility.
- Conductivity (σ) is given by: σ = 1 / ρ
- The relation between conductivity and carrier density is:
- Here, q = Charge of an electron = 1.6 × 10⁻¹⁹ C
Calculation:
Resistivity of Si, ρ = 3.16 × 10³ Ω·m
Electron mobility, μₑ = 0.14 m²/V·s
Hole mobility, μₕ = 0.06 m²/V·s
⇒ Conductivity, σ = 1 / ρ = 1 / (3.16 × 10³)
⇒ σ = 3.16 × 10⁻⁴ S/m
⇒ Using the formula,
nᵢ = σ / (q × (μₑ + μₕ))
⇒ nᵢ = (3.16 × 10⁻⁴) / (1.6 × 10⁻¹⁹ × (0.14 + 0.06))
⇒ nᵢ = (3.16 × 10⁻⁴) / (1.6 × 10⁻¹⁹ × 0.20)
⇒ nᵢ = (3.16 × 10⁻⁴) / (3.2 × 10⁻²⁰)
⇒ nᵢ = 0.987 × 10¹⁶
⇒ nᵢ ≈ 1.00 × 10¹⁶ m⁻³
∴ The intrinsic carrier density of Si is 1.00 × 10¹⁶ m⁻³.
P-Type Semiconductor Question 3:
Which of the following represents the energy band diagram of a semi-conductor?
Answer (Detailed Solution Below)
P-Type Semiconductor Question 3 Detailed Solution
Concept:
- Forbidden energy gap (ΔEg): The energy gap between the conduction band and valence band is known as the forbidden energy gap i.e.,
ΔEg = (C.B)min - (V.B)max
- No free electron is present in the forbidden energy gap.
- The width of the forbidden energy gap depends upon the nature of the substance.
- As the temperature increases, the forbidden energy gap decreases very slightly.
EXPLANATION:
EXPLANATION:
Conductors:
- Conductors allow an electric current to flow through them.
- There is no forbidden gap between the valence band and conduction band which results in the overlapping of both the bands.
- The number of free electrons available at room temperature is large. Ex. Gold, Aluminium, Silver, Copper, etc.
Insulators:
- These substances do not allow electricity to pass through them.
- They have high resistivity and very low conductivity.
- The energy gap in the insulator is very high up to 7eV.
- The material cannot conduct because the movement of the electrons from the valence band to the conduction band is not possible. Ex. Glass, wood, etc.
Semiconductors:
- Germanium and Silicon are the most preferable material whose electrical properties lie in between semiconductors and insulators.
- The energy band diagram of the semiconductor is shown where the conduction band is empty and the valence band is completely filled but the forbidden gap between the two bands is very small which is about 1eV.
- From the above explanation, it is clear that the forbidden energy gap in an intrinsic semiconductor is of the order of 1eV. Hence, option 1 is correct.
P-Type Semiconductor Question 4:
Which of the following can be used in the fabrication of p-type semiconductor?
Answer (Detailed Solution Below)
P-Type Semiconductor Question 4 Detailed Solution
Semiconductor:
Semiconductors are materials that have a conductivity between conductors and insulators.
Semiconductors are made of compounds such as gallium arsenide or pure elements, such as germanium or silicon.
There are two types of semiconductors:
N-type Semiconductor
P-type Semiconductor
N-type Semiconductor | P-type Semiconductor |
In an n-type semiconductor, pentavalent impurity from the V group is added to the pure semiconductor. |
In a p-type semiconductor, trivalent impurity from the III group elements is added as the impurity. |
Examples of pentavalent impurities are Arsenic, Antimony, Bismuth, etc. | Trivalent impurities like Aluminium, Indium, and Gallium are added to the intrinsic semiconductor. |
The pentavalent impurities provide extra electrons and are termed as donor atoms. | The trivalent impurities added provides extra holes known as the acceptor atom. |
Electrons are the majority charge carriers in n-type semiconductors. | The majority of charge carriers in a p-type semiconductor are holes. |
P-Type Semiconductor Question 5:
For P-type semiconductor, the dopant is
Answer (Detailed Solution Below)
P-Type Semiconductor Question 5 Detailed Solution
In a P-type semiconductor material, holes are generated because a trivalent impurity atom has one less electron than the surrounding silicon atom. Thus, leaving a vacancy in a covalent bond that acts as a hole. The presence of a hole does not make the semiconductor material positively charge because in an impurity atom, no. of electron and proton is equal before and after the doping, and the same applies for the silicon atom.
Thus, p-type semiconductor crystal remains neutral.
Important Points:
- Extrinsic P-type Semiconductor is formed when a trivalent impurity is added to a pure semiconductor.
- Example of trivalent impurity is Boron, Gallium, and Indium.
- Trivalent impurity like boron has 3 valence electrons.
- Each atom of the impurity fits in the silicon crystal by forming covalent bonds with the surrounding silicon atoms.
- The dopant boron atom has one less electron than surrounding silicon and thus vacancy is generated that acts as a hole.
Top P-Type Semiconductor MCQ Objective Questions
For P-type semiconductor, the dopant is
Answer (Detailed Solution Below)
P-Type Semiconductor Question 6 Detailed Solution
Download Solution PDFIn a P-type semiconductor material, holes are generated because trivalent impurity atom has one less electron than surrounding silicon atom. Thus, leaving a vacancy in a covalent bond that acts as a hole. Presence of hole does not make the semiconductor material positively charge because in an impurity atom, no. of electron and proton is equal before and after the doping, and the same applies for the silicon atom.
Thus, p-type semiconductor crystal remains neutral.
Important Points:
- Extrinsic P-type Semiconductor is formed when a trivalent impurity is added to a pure semiconductor
- Example of trivalent impurity are Boron, Gallium and Indium
- Trivalent impurity like boron, have 3 valence electrons
- Each atom of the impurity fits in the silicon crystal by forming covalent bonds with the surrounding silicon atoms
- The dopant boron atom has one less electron than surrounding silicon and thus vacancy is generated that acts as a hole
Which of the following represents the energy band diagram of a semi-conductor?
Answer (Detailed Solution Below)
P-Type Semiconductor Question 7 Detailed Solution
Download Solution PDFConcept:
- Forbidden energy gap (ΔEg): The energy gap between the conduction band and valence band is known as the forbidden energy gap i.e.,
ΔEg = (C.B)min - (V.B)max
- No free electron is present in the forbidden energy gap.
- The width of the forbidden energy gap depends upon the nature of the substance.
- As the temperature increases, the forbidden energy gap decreases very slightly.
EXPLANATION:
EXPLANATION:
Conductors:
- Conductors allow an electric current to flow through them.
- There is no forbidden gap between the valence band and conduction band which results in the overlapping of both the bands.
- The number of free electrons available at room temperature is large. Ex. Gold, Aluminium, Silver, Copper, etc.
Insulators:
- These substances do not allow electricity to pass through them.
- They have high resistivity and very low conductivity.
- The energy gap in the insulator is very high up to 7eV.
- The material cannot conduct because the movement of the electrons from the valence band to the conduction band is not possible. Ex. Glass, wood, etc.
Semiconductors:
- Germanium and Silicon are the most preferable material whose electrical properties lie in between semiconductors and insulators.
- The energy band diagram of the semiconductor is shown where the conduction band is empty and the valence band is completely filled but the forbidden gap between the two bands is very small which is about 1eV.
- From the above explanation, it is clear that the forbidden energy gap in an intrinsic semiconductor is of the order of 1eV. Hence, option 1 is correct.
Majority carriers of P type material
Answer (Detailed Solution Below)
P-Type Semiconductor Question 8 Detailed Solution
Download Solution PDFP-type semiconductor:
- Extrinsic P-type Semiconductor is formed when a trivalent impurity is added to a pure semiconductor
- Example of trivalent impurity are Boron, Gallium, and Indium
- Trivalent impurity like boron has 3 valence electrons.
- Each atom of the impurity fits in the silicon crystal by forming covalent bonds with the surrounding silicon atoms
- The dopant boron atom has one less electron than surrounding silicon and thus vacancy is generated that acts as a hole.
- Therefore, holes are in majority in the p-type semiconductors.
Pentavalent impurities:
Impurity atoms with 5 valence electrons produce n-type semiconductors by contributing an extra electron.
This is as explained in the figure:
P-Type Semiconductor Question 9:
For P-type semiconductor, the dopant is
Answer (Detailed Solution Below)
P-Type Semiconductor Question 9 Detailed Solution
In a P-type semiconductor material, holes are generated because trivalent impurity atom has one less electron than surrounding silicon atom. Thus, leaving a vacancy in a covalent bond that acts as a hole. Presence of hole does not make the semiconductor material positively charge because in an impurity atom, no. of electron and proton is equal before and after the doping, and the same applies for the silicon atom.
Thus, p-type semiconductor crystal remains neutral.
Important Points:
- Extrinsic P-type Semiconductor is formed when a trivalent impurity is added to a pure semiconductor
- Example of trivalent impurity are Boron, Gallium and Indium
- Trivalent impurity like boron, have 3 valence electrons
- Each atom of the impurity fits in the silicon crystal by forming covalent bonds with the surrounding silicon atoms
- The dopant boron atom has one less electron than surrounding silicon and thus vacancy is generated that acts as a hole
P-Type Semiconductor Question 10:
Which of the following can be used in the fabrication of p-type semiconductor?
Answer (Detailed Solution Below)
P-Type Semiconductor Question 10 Detailed Solution
Semiconductor:
Semiconductors are materials that have a conductivity between conductors and insulators.
Semiconductors are made of compounds such as gallium arsenide or pure elements, such as germanium or silicon.
There are two types of semiconductors:
N-type Semiconductor
P-type Semiconductor
N-type Semiconductor | P-type Semiconductor |
In an n-type semiconductor, pentavalent impurity from the V group is added to the pure semiconductor. |
In a p-type semiconductor, trivalent impurity from the III group elements is added as the impurity. |
Examples of pentavalent impurities are Arsenic, Antimony, Bismuth, etc. | Trivalent impurities like Aluminium, Indium, and Gallium are added to the intrinsic semiconductor. |
The pentavalent impurities provide extra electrons and are termed as donor atoms. | The trivalent impurities added provides extra holes known as the acceptor atom. |
Electrons are the majority charge carriers in n-type semiconductors. | The majority of charge carriers in a p-type semiconductor are holes. |
P-Type Semiconductor Question 11:
Doping material for p-type semiconductor is:
Answer (Detailed Solution Below)
P-Type Semiconductor Question 11 Detailed Solution
- Extrinsic p-Type Semiconductor is formed when a trivalent impurity is added to a pure semiconductor.
- Example of trivalent impurity are Boron, Gallium, and Indium
- Trivalent impurity like boron, have 3 valence electrons.
- Each atom of the impurity fits in the silicon crystal by forming covalent bonds with the surrounding silicon atoms.
- The dopant boron atom has one less electron than surrounding silicon and thus vacancy is generated that acts as a hole.
P-Type Semiconductor Question 12:
Which of the following represents the energy band diagram of a semi-conductor?
Answer (Detailed Solution Below)
P-Type Semiconductor Question 12 Detailed Solution
Concept:
- Forbidden energy gap (ΔEg): The energy gap between the conduction band and valence band is known as the forbidden energy gap i.e.,
ΔEg = (C.B)min - (V.B)max
- No free electron is present in the forbidden energy gap.
- The width of the forbidden energy gap depends upon the nature of the substance.
- As the temperature increases, the forbidden energy gap decreases very slightly.
EXPLANATION:
EXPLANATION:
Conductors:
- Conductors allow an electric current to flow through them.
- There is no forbidden gap between the valence band and conduction band which results in the overlapping of both the bands.
- The number of free electrons available at room temperature is large. Ex. Gold, Aluminium, Silver, Copper, etc.
Insulators:
- These substances do not allow electricity to pass through them.
- They have high resistivity and very low conductivity.
- The energy gap in the insulator is very high up to 7eV.
- The material cannot conduct because the movement of the electrons from the valence band to the conduction band is not possible. Ex. Glass, wood, etc.
Semiconductors:
- Germanium and Silicon are the most preferable material whose electrical properties lie in between semiconductors and insulators.
- The energy band diagram of the semiconductor is shown where the conduction band is empty and the valence band is completely filled but the forbidden gap between the two bands is very small which is about 1eV.
- From the above explanation, it is clear that the forbidden energy gap in an intrinsic semiconductor is of the order of 1eV. Hence, option 1 is correct.
P-Type Semiconductor Question 13:
A sample of GaAs doped with NA = 1017 cm-3. For GaAs intrinsic concentration is n = 2.2 × 106 cm-3, mobility of electron is μn = 5300 cm2/V-sec, and mobility of hole is μp = 230 cm2/V sec.
If the sample is illuminated such that the excess electron concentration is 1016 cm-3. What will the conductivity [in (Ω-cm)-1] of this sample, when the light is ON?
Answer (Detailed Solution Below) 12.48 - 12.60
P-Type Semiconductor Question 13 Detailed Solution
Concept:
The conductivity for a doped semiconductor is obtained as:
σ = q n0 μn = q p0 μp
where,
ni = Intrinsic carrier concentration.
μn = electron mobility
μp = Hole mobility
When a semiconductor crystal is optically excited, one hole is created for every electron, i.e. electron-hole pass are created.
Application:
When the light is ON, excess electron and holes are generated in pairs, i.e.
Δp = Δn = 1016 cm3
Before Illumination:
NA = 1017 cm-3 and ni = 2.2 × 106 cm-3
Since NA ≫ ni, the excess hole concentration at thermal equilibrium will be:
p0 = NA = 1017 cm-3
The electron concentration using mass-action law is obtained as:
\({n_0} = \frac{{n_i^2}}{{{p_0}}}\)
\({n_0} = \frac{{{{\left( {2.2 \times {{10}^6}} \right)}^2}}}{{{{10}^{17}}}} = 4.8 \times {10^{ - 5}}c{m^{ - 3}}\)
The electron concentration before illumination is negligible.
After illumination:
When an electron is generated optically, one hole is also created, i.e. they always occur in pairs.
∴ The excess hole concentration and excess electron concentration will be the same, i.e.
Δp = Δn = 1016 cm-3
Now, the electron and hole concentration after illumination will be:
n = n0 + Δn
n = 4.8 × 10-5 + 1016
n = 1016
Similarly,
p = p0 + Δp
p = 1017 + 1016 cm-3
p = 11 × 1016 cm-3
∴ the conductivity of the given sample when the light is ON will be:
σ = q(n0 + Δn)μn + q(p0 + Δp)μp
σ = q[(1016)μn + (11 × 1016)μp]
= (1.6 × 10-19) (1016 × 5300 + (11 × 1016) (230))
= 1.6 × 10-19 (5.3 × 1019 + 2.53 × 1019)
= 1.6 × (5.3 + 2.53)
σ = 12.528 (Ω-cm)-1
P-Type Semiconductor Question 14:
Majority carriers of P type material
Answer (Detailed Solution Below)
P-Type Semiconductor Question 14 Detailed Solution
P-type semiconductor:
- Extrinsic P-type Semiconductor is formed when a trivalent impurity is added to a pure semiconductor
- Example of trivalent impurity are Boron, Gallium, and Indium
- Trivalent impurity like boron has 3 valence electrons.
- Each atom of the impurity fits in the silicon crystal by forming covalent bonds with the surrounding silicon atoms
- The dopant boron atom has one less electron than surrounding silicon and thus vacancy is generated that acts as a hole.
- Therefore, holes are in majority in the p-type semiconductors.
Pentavalent impurities:
Impurity atoms with 5 valence electrons produce n-type semiconductors by contributing an extra electron.
This is as explained in the figure:
P-Type Semiconductor Question 15:
The ambipolar transport equation for p-type semiconductor is
\(\rm {{\text{D}}_{\text{n}}}\frac{{{\partial ^2}\left( \delta{{\text{n}}} \right)}}{{\partial {{\text{x}}^2}}} + {{\text{}}\mu_{\text{n}}}{\text{E}}\frac{{\partial \left(\delta {{\text{n}}} \right)}}{{\partial {\text{x}}}} + {\text{g'}} - \frac{{{\delta\text{n}}}}{{{{\text{ }}\tau_{{\text{no}}}}}} = \frac{{\partial \left( \delta{{\text{n}}} \right)}}{{\partial {\text{t}}}}\), where all notations have standard meaning. Which term is set to zero when no excess carrier recombination is assumed?
Answer (Detailed Solution Below)
P-Type Semiconductor Question 15 Detailed Solution
Common ambipolar transport equation simplifications are as shown below. In achieving the simplifications the complete term (along with constant) has been shown equated to zero.
Simplification |
Effect (for p-type) |
1) Steady state |
\(\frac{{\partial \left( {{\rm{\delta n}}} \right)}}{{\partial {\rm{t}}}} = 0\) |
2) Uniform distribution of excess carriers (uniform generation rate) |
\({{\rm{D}}_{\rm{n}}}\frac{{{\partial ^2}\left( {{\rm{\delta n}}} \right)}}{{\partial {{\rm{x}}^2}}} = 0\) |
3) Zero electric field |
\({\rm{E}}\frac{{\partial \left( {{\rm{\delta n}}} \right)}}{{\partial {\rm{x}}}} = 0\) |
4) No excess carrier generation |
\(\rm{g}’=0\) |
5) No excess carrier recombination (infinite lifetime) |
\(\frac{{{\rm{\delta n}}}}{{{{\rm{\tau }}_{{\rm{no}}}}}} = 0\) |