Marks Based MCQ Quiz - Objective Question with Answer for Marks Based - Download Free PDF

Given:

Number of students = 30

Average score of 12 students = 60

Average score of remaining students = 60

Formula used:

Class Average = (Sum of all scores) ÷ (Total number of students)

Sum of scores = Average × Number of students

Calculation:

Sum of scores of first 12 students = 60 × 12 = 720

Sum of scores of remaining 18 students = 60 × 18 = 1080

Total sum of scores = 720 + 1080 = 1800

⇒ Class Average = 1800 ÷ 30 = 60

∴ The correct answer is option (2).

Given:

Last Year's Marks: Mathematics (M₁) = 60, English (E₁) = 75

This Year's English Marks (E₂) = 60

Formula Used:

Since the marks are in proportion, the ratio of Mathematics marks to English marks is constant.

⇒ M₁ / E₁ = M₂ / E₂

Calculations:

Let this year's Mathematics marks be M₂.

Set up the proportion:

⇒ 60 / 75 = M₂ / 60

Simplify the ratio 60/75 by dividing both by 15:

⇒ 4 / 5 = M₂ / 60

Solve for M₂:

⇒ M₂ = (4 / 5) × 60

⇒ M₂ = 4 × 12

⇒ M₂ = 48

∴ S's Mathematics marks are 48.

Given:

Average score of 60 students = 52

Number of students in the class initially = 60

Average score of 8 boys who left = 40

Average score of 10 boys who joined = 43

Formula used:

New average = ${\displaystyle \frac{\text{Total sum of scores after changes}}{\text{Total number of students after changes}}}$

Calculation:

Sum of scores of 60 students = 60 × 52 = 3120

Sum of scores of 8 boys who left = 8 × 40 = 320

Sum of scores of 10 boys who joined = 10 × 43 = 430

Total sum of scores after changes = 3120 - 320 + 430 = 3230

Total number of students after changes = 60 - 8 + 10 = 62

New average = ${\displaystyle \frac{3230}{62}}$

⇒ New average = 52.1

∴ The correct answer is option (2).

Given:

Marks obtained = 120

Marks needed to pass = 55% of total marks

Marks required to pass = 120 + 78

Formula used:

Pass marks = 55% of total marks

Calculation:

Marks required to pass = 120 + 78

⇒ 198 = 0.55 x Total Marks

⇒ Total Marks = ${\displaystyle \frac{198}{0.55}}$

⇒ Total Marks = 360

∴ The correct answer is option (2).

Marks required to pass = 975

Priya's marks = 870

Priya was declared failed by = 7%

Formula Used:

Percentage decrease = $\frac{(Requiredmarks-Obtainedmarks)}{Maximummarks}\times 100$

Calculation:

Let the maximum aggregate marks be x.

Priya was declared failed by 7%, so:

$\frac{(975-870)}{x}\times 100=7$

⇒ $\frac{105}{x}\times 100=7$

⇒ $\frac{10500}{x}=7$

⇒ x = $\frac{10500}{7}$

⇒ x = 1500

The maximum aggregate marks that a student can get in the examination is 1500.

Given:

John got 20% marks in an exam.

John failed by 10 marks.

Jack got 35% marks.

Jack got 20 more than the minimum passing marks.

Calculation:

As per the question,

35 % - 20% = 10 + 20 

⇒ 15% = 30

⇒ 100% = 200

So, Pass mark = 200 × 20/100 + 10 = 50

So, Passing percentage = (50/200) × 100 = 25%

∴ The percentage of minimum marks required to pass is 25%

Given

The candidate secured 75% marks in Paper A, 80% marks in Paper B, and 60% marks in Paper C

Formula

The weighted average of values is the sum of the weight times values divided by the sum of the weights.

Calculation

Let the maximum mark on each paper be 100.

Marks in Paper A = 75% of 100 = 75

Marks in Paper B = 80% of 100 = 80

Marks in Paper C = 60% of 100 = 60

Weightage of Paper A = 40% of 75 = 30

Weightage of Paper B = 50% of 80 = 40

Weightage of Paper C = 10% of 60= 6

The weighted percentage of marks obtained by the candidate

= (30 + 40 + 6)/100 × 100

= 76%

The weighted percentage of marks obtained by the candidate is 76%.

Shortcut Trick

Given:

In a competitive exam, the marks obtained by Sam are 19% less than those of Peter.

Calculation:

Let Peter gets 100 marks

Then Sam gets 100 - 19 = 81 marks

The marks obtained by Peter is more than the marks obtained by Sam ,

⇒ $\frac{19}{81}$ × 100 = 23.46%

∴ The correct option is 4

Given:

Failed by = 14 marks

Marks obtained = 210 marks

Concept used:

If he failed by means we need to add that and if he passed by we will subtract it.

Calculations:

Let, the total marks is x

⇒ (35x/100) = 210 + 14

⇒ (35x/100) = 224

⇒ x = 22400/35

⇒ x = 640

The answer is 640 marks.

Marks required to pass = 975

Priya's marks = 870

Priya was declared failed by = 7%

Formula Used:

Percentage decrease = $\frac{(Requiredmarks-Obtainedmarks)}{Maximummarks}\times 100$

Calculation:

Let the maximum aggregate marks be x.

Priya was declared failed by 7%, so:

$\frac{(975-870)}{x}\times 100=7$

⇒ $\frac{105}{x}\times 100=7$

⇒ $\frac{10500}{x}=7$

⇒ x = $\frac{10500}{7}$

⇒ x = 1500

The maximum aggregate marks that a student can get in the examination is 1500.

Given:

Marks obtained = 120

Marks needed to pass = 55% of total marks

Marks required to pass = 120 + 78

Formula used:

Pass marks = 55% of total marks

Calculation:

Marks required to pass = 120 + 78

⇒ 198 = 0.55 x Total Marks

⇒ Total Marks = ${\displaystyle \frac{198}{0.55}}$

⇒ Total Marks = 360

∴ The correct answer is option (2).

Given:

Last Year's Marks: Mathematics (M₁) = 60, English (E₁) = 75

This Year's English Marks (E₂) = 60

Formula Used:

Since the marks are in proportion, the ratio of Mathematics marks to English marks is constant.

⇒ M₁ / E₁ = M₂ / E₂

Calculations:

Let this year's Mathematics marks be M₂.

Set up the proportion:

⇒ 60 / 75 = M₂ / 60

Simplify the ratio 60/75 by dividing both by 15:

⇒ 4 / 5 = M₂ / 60

Solve for M₂:

⇒ M₂ = (4 / 5) × 60

⇒ M₂ = 4 × 12

⇒ M₂ = 48

∴ S's Mathematics marks are 48.

Given:

Number of students = 30

Average score of 12 students = 60

Average score of remaining students = 60

Formula used:

Class Average = (Sum of all scores) ÷ (Total number of students)

Sum of scores = Average × Number of students

Calculation:

Sum of scores of first 12 students = 60 × 12 = 720

Sum of scores of remaining 18 students = 60 × 18 = 1080

Total sum of scores = 720 + 1080 = 1800

⇒ Class Average = 1800 ÷ 30 = 60

∴ The correct answer is option (2).

Given:

Average score of 60 students = 52

Number of students in the class initially = 60

Average score of 8 boys who left = 40

Average score of 10 boys who joined = 43

Formula used:

New average = ${\displaystyle \frac{\text{Total sum of scores after changes}}{\text{Total number of students after changes}}}$

Calculation:

Sum of scores of 60 students = 60 × 52 = 3120

Sum of scores of 8 boys who left = 8 × 40 = 320

Sum of scores of 10 boys who joined = 10 × 43 = 430

Total sum of scores after changes = 3120 - 320 + 430 = 3230

Total number of students after changes = 60 - 8 + 10 = 62

New average = ${\displaystyle \frac{3230}{62}}$

⇒ New average = 52.1

∴ The correct answer is option (2).

Given:

John got 20% marks in an exam.

John failed by 10 marks.

Jack got 35% marks.

Jack got 20 more than the minimum passing marks.

Calculation:

As per the question,

35 % - 20% = 10 + 20 

⇒ 15% = 30

⇒ 100% = 200

So, Pass mark = 200 × 20/100 + 10 = 50

So, Passing percentage = (50/200) × 100 = 25%

∴ The percentage of minimum marks required to pass is 25%