Question
Download Solution PDFWater flows in a horizontal pipe of non-uniform area of cross-section at a pressure difference of 1.6 cm of mercury. If the velocity of water at the larger cross-section of pipe is 50 cm/s, find the velocity of water at the other end?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
Applying Bernoulli's theorem,
CALCULATION:
Given: v1 = 50 cm/s = 0.5 m/s
P1 - P2 = 0.016 × 13600 × 9.81 = 2134.65 Pa
Z1 = Z2 Horizontal pipe, v2 = ?
⇒ v2 =
Hence the correct option is option 3
Additional Information
- Bernoulli's theorem can also be written in terms of the head as,
- It is valid only for continuous stream and incompressible flow.
Assumptions of Bernoulli's theorem:
- The fluid is ideal (has zero viscosity)
- The flow is steady.
- The flow is one-dimensional.
- The flow is incompressible.
Last updated on Jun 19, 2025
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