Two silicon diodes with a forward voltage drop of 0.7 V, are used in the circuit shown below. The range of input voltage Vi for which the output voltage Vo = Vi is :

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  1. −0.3 V < Vi < 1.3 V 
  2. −0.3 V < Vi < 2 V
  3. −1.0 V < Vi < 2 V
  4. −1.7 V < Vi < 2.7 V

Answer (Detailed Solution Below)

Option 4 : −1.7 V < Vi < 2.7 V
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Concept:

Two silicon diodes with a forward voltage drop of 0.7 V are used in the given clipping circuit.

The diodes are arranged such that D1 is connected to a –1 V source and D2 is connected to a +2 V source, with output voltage Vo taken from the junction between the resistor and the two diodes.

We need to find the range of input voltage Vi for which Vo = Vi, i.e., when both diodes are in OFF condition and do not affect the output.

Analysis:

Condition for D1 (left diode) to turn ON:

D1 conducts when anode-to-cathode voltage ≥ 0.7 V.

Anode of D1 is at Vi, cathode is at –1 V.

So,

To keep D1 OFF:

Condition for D2 (right diode) to turn ON:

D2 conducts when cathode-to-anode voltage ≥ 0.7 V.

Cathode of D2 is at Vi, anode is at +2 V.

So,

To keep D2 OFF:

Result:

For both diodes to remain OFF (and hence Vo = Vi), the valid range is:

−1.7 V < V< 2.7 V

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