The value of \(I = \mathop \smallint \limits_{ - 1}^1 {e^{\left| x \right|}}dx\) is equal to

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  1. (e - 1)
  2. 2(e - 1)
  3. 3(e - 1)
  4. 2(1 - e)

Answer (Detailed Solution Below)

Option 2 : 2(e - 1)
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Explanation:

\(I=\mathop \smallint \limits_{ - 1}^1 {e^{\left| x \right|}}dx.\)

\(I= \mathop \smallint \limits_{ - 1}^0 {e^{ - x}}dx + \mathop \smallint \limits_0^1 {e^x}dx\)

\(I= \left[ { - {e^{ - x}}} \right]_{-1}^0 + \left[ {{e^x}} \right]_0^1\)

I = [-e-0 + e1] + [e1 - e0]

I = -1 + e1 + e - 1

I = 2 (e - 1)
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