The relationship between peak value of current I0 and RMS current Irms is:

  1. \(I_{rms} = \frac{I_0}{\sqrt2}\)
  2. \(I_{rms} = \frac{I_0}{2}\)
  3. Irms = I0
  4. Irms = √2I0

Answer (Detailed Solution Below)

Option 1 : \(I_{rms} = \frac{I_0}{\sqrt2}\)
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The correct answer is option 1) i.e. \(I_{rms} = \frac{I_0}{\sqrt2}\)

CONCEPT:

  • Peak value: The maximum value attained by the alternating current during a cycle is called its peak value. Considering alternating current as a sinusoidal wave, the peak value is its amplitude or crest value.

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  • RMS value: RMS current is that value of steady current which when flowing through a given resistance for a given period of time, produces the same quantity of heat like that of an alternating current flowing through the same resistance and for same time period.
    • It is also known as the effective value of alternating current.

The RMS current Irms is related to the peak current I0 as:

 \(I_{rms} = \frac{I_0}{√2}\)

EXPLANATION:

The correct answer is \(I_{rms} = \frac{I_0}{√2}\)

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