The reducible representation, Γ, in the table is equal to the following superposition of the irreducible representations of C2v point group.

C2v

E

 C2

σv

A1

1

1

 1

1

A2

1

1

−1

−1

B1

1

−1

1

−1

B2

1

−1

−1

1

 

 

 

 

 

Γ

8

−2

−6

4

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  1. A1 ⊕ 2A2 ⊕ 5B1
  2. A1 ⊕ 2A2 ⊕ 5B2
  3. 5A1 ⊕ A2 ⊕ 2B1
  4. A1 ⊕ 5A2 ⊕ 2B2

Answer (Detailed Solution Below)

Option 2 : A1 ⊕ 2A2 ⊕ 5B2
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Seating Arrangement
10 Qs. 20 Marks 15 Mins

Detailed Solution

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Concept:

  • The sum of the squares of the dimensions of all the irreducible representations is equal to the order of the group.

∑di2 = h, where h = order of the group, and d = dimension

Explanation:-

  • The irreducible representations can be obtained from reducible representations from the formula,

where h is the order of the group,

Xi is the character of the reducible representation,

Yi is the character of the irreducible representation,

Zi is the coefficient of the symmetry element.

  • The characters of a reducible representation ΓR under the C2v point group are presented below:

C2v

E

 C2

σv

A1

1

1

 1

1

A2

1

1

−1

−1

B1

1

−1

1

−1

B2

1

−1

−1

1

 

 

 

 

 

Γ

8

−2

−6

4

  • The order of the group ​is,

= 12 + 12 + 12 + 12

= 4

  • The correct coefficients of the irreducible representations A1 will be,

1

  • The correct coefficients of the irreducible representations A2 will be,

2

  • The correct coefficients of the irreducible representations B1 will be,

0

  • The correct coefficients of the irreducible representations B2 will be,

= 2
Thus, the irreducible representations of the C2v point group is

A1 ⊕ 2A2 ⊕ 0B1 ⊕ 5B2

A1 ⊕ 2A2 ⊕ 5B2

Conclusion:-

Hence, A1 ⊕ 2A2 ⊕ 5Bis correct.

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