The permissible stress in a filled weld is 100 N/mm2. The fillet weld has equal leg lengths of 15 mm each. The allowable shearing load on weldament per cm length of the weld is

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  1. 22.5 kN
  2. 15.0 kN
  3. 10.6 kN
  4. 7.5 kN

Answer (Detailed Solution Below)

Option 3 : 10.6 kN
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Explanation:

SSC JE ME Full test-7 Images-Q15

Minimum area of the weld or throat area,

\(A = t \times l = 0.707s \times l\)

If \({\sigma _t}\) is the allowable tensile stress for the weld metal, then the tensile strength of the joint for single fillet weld,

\(P = Throat\;area\; \times \;Allowable\;tensile\;stress\; = \;0.707\;s\; \times \;l\; \times {\sigma _t}\)

Where s is Leg or size of weld; t is throat thickness; l is length of weld=1cm=10mm

\(\begin{array}{l} t = s \times sin{45^o} = 0.707s\\ = 0.707\; \times \;15\; \times \;10\; \times \;100 = 10.6~kN \end{array}\)

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