Question
Download Solution PDFThe next state table of a 2-bit saturating up-counter is given below.
|
Q1 |
Q0 |
\({Q_{1}^{+}}\) |
\({Q_{0}^{+}}\) |
|
0 |
0 |
0 |
1 |
|
0 |
1 |
1 |
0 |
|
1 |
0 |
1 |
1 |
|
1 |
1 |
1 |
1 |
The counter is built as a synchronous sequential circuit using T flip-flops. The expressions for T1 and T0 are
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Output of T flip flop will change when T = 1 and remain same when T = 0
Excitation table for T flip flop
|
Q1 |
Q0 |
\(Q_{1}^{+}\) |
\(Q_{0}^{+}\) |
T1 |
T0 |
|
0 |
0 |
0 |
1 |
0 |
1 |
|
0 |
1 |
1 |
0 |
1 |
1 |
|
1 |
0 |
1 |
1 |
0 |
1 |
|
1 |
1 |
1 |
1 |
0 |
0 |
From this table,
T1 = Q̅1Q0
T0 = Q̅1 + Q̅0
Important Point:
T0 → NAND Gate (function)
Tips:
If unable to write the function then construct the K- Map of two variable with Q1 and Q0 as input
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