The mean and median of the distribution are 10 and 12 respectively, then the mode equals to

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SSC CGL Tier-II ( JSO ) 2021 Official Paper ( Held On: 10 August 2022 )
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  1. 20
  2. 16
  3. 14
  4. 18

Answer (Detailed Solution Below)

Option 2 : 16
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Detailed Solution

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The correct answer is16.

Key Points 

  • The formula used to derive this result is Mean - Mode = 3 (Mean -Median).
    The solution to this problem is:
  • The Mean in a frequency distribution is the average of all the observations. The average of all the observations is done by adding them up and dividing them by the total number of observations in a frequency distribution.
  • The Median is the middlemost value of a distribution when all the values of the observation are arranged from ascending to descending order.
  • Mode is the value that has the highest frequency.
Additional Information 
  • The relation between Mean, Median and Mode determines the nature of the frequency distribution curve.
  • If Mean=Median=Mode then the distribution curve is symmetrical.
  • If Mean>Median>Mode then the distribution curve is positively skewed.
  • The Mode>Median>Mean then the distribution curve is negatively skewed.

Hence, the mean and median of the distribution are 10 and 12 respectively, then the mode equals to the mean and median of the distribution are 10 and 12 respectively, then the mode is 16.

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