The maximum bending moment caused by a set of concentrated moving loads is

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ESE Civil 2016 Paper 1: Official Paper
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  1. Always at the mind-point of span
  2. Between the mid-point and concentrated load next to the mid-point of the span
  3. Not definable
  4. Always under a load close to the centroid of the set of loads.

Answer (Detailed Solution Below)

Option 4 : Always under a load close to the centroid of the set of loads.
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Detailed Solution

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Concept:

Maximum moment under a load:

Let a train of concentrated loads W1, W2, W3,… move on a simply supported beam AB from left to right as shown in Figure 5.18. Now, the condition for moment to be maximum under wheel load W2 is required. Let R be the resultant of all loads. Let its distance from W2 be d and from support A be x (Refer figure 5.18)

F1 A.M Madhu 01.06.20 D29

Now, \({R_A}\; = \;\frac{{R\left( {L - x} \right)}}{L}\)

Therefore, moment under load W2

M = RA (x + d) – Rd

\(= \;R\left[ {\frac{{L - x}}{L}} \right]\left( {x\; + \;d} \right) - Rd\)

\(= \;\frac{R}{L}\left[ {Lx - {x^2}\; + \;Ld - xd} \right] - Rd\)

For the moment to be maximum

\(\frac{{dM}}{{dx}}\; = \;0\; = \;\frac{R}{L}\left[ {L - 2x - d} \right]\)

Or  \(x\; = \;\frac{L}{2} - \frac{d}{2}\)       ---(1)

Distance of W2 from A

\(= \;x\; + \;d\; = \;\frac{L}{2} - \frac{d}{2}\; + \;d\)

\( = \;\frac{L}{2}\; + \;\frac{d}{2}\)         ---(2)

From (1) and (2) we conclude, for moment to be maximum under any particular load, the load and the resultant should be equidistant from the mid-span.

To get maximum bending moment under a chosen wheel load,keep the loads such that the chosen wheel load and resultant are at equal distance from centre. Then, maximum BM occurs under choosen wheel load (But not at centre).  

So here the appropriate option will be option D.

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