Question
Download Solution PDFThe equation of the line passing through (0, 0) and perpendicular to the line 2x + 3y + 5 = 0, is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The product of the slopes of a pair of perpendicular lines is -1.
Calculation:
The slope of the line 2x + 3y + 5 = 0 is m = \(-\frac{2}{3}\).
∴ The slope of the line perpendicular to it, must be n = \(\frac{3}{2}\).
So, let the equation of the required line be y = \(\frac{3}{2}\)x + c.
Since this line passes through (0, 0), we must have:
0 = 0 + c
⇒ c = 0.
∴ The required equation of the line is y = \(\frac{3}{2}\)x; which can also be written as 3x - 2y = 0.
Last updated on Jun 20, 2025
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