Question
Download Solution PDFThe electric field due to a point charge at distance ‘r’ is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe electric field at a distance 'r' due to a point charge is given by:
\(\bar E= \frac{Q}{{4\pi {\epsilon_0}{r^2}}} \hat a_r\)
r = distance from the point charge
âr = unit direction vector
This is explained with the help of the following diagram:
As the distance from the point charge decreases the magnitude also decreases.
Important Points:
- The direction is radial: outward for +|Q| and inward for -|Q|
- Magnitude: Constant on any spherical shell
- Flux through any shell enclosing Q is the same: EAAA = EBAB
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